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Physics-

General

Easy

Question

Two bodies of masses 5kg and 4kg are arranged on a table as shown in figure. The acceleration of 5kg block is.

g
$\frac{4}{9}$ g
$g / 5$
$\frac{5}{9}$ g

The correct answer is: $fraction numerator 4 over denominator 9 end fraction$ g

$a equals fraction numerator 4 over denominator 4 plus 5 end fraction g$
$equals fraction numerator 4 over denominator 9 end fraction g$

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Three blocks are connected as shown in the figure on a horizontal friction less table. If $M_{1} = 1 k g, M_{2} = 8 k g, M_{3} = 27 k g and T_{3} = 36 N,$ then T₂ will be.

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Two blocks of masses 2kg and 1kg are in contact with each other on a friction less table. When a horizontal force of 3N is applied on the block of mass 2kg, the value of the force of contact between the two blocks is.

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Two masses m₁ and m₂ are placed on a smooth surface horizontally and connected by a light string as shown in figure A force F is applied on mass m₁, then the tension in the string T₂ is.

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If the angle of friction is 45 $degree$ , then the coefficient of static friction is.

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A block of mass 2kg lies on a horizontal surface and it is subjected to a vertical downward force 30N as shown in figure. The contact force between the block and surface is.

A block of mass 2kg lies on a horizontal surface and it is subjected to a vertical downward force 30N as shown in figure. The contact force between the block and surface is.

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The free body diagram of block 'm' is

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If $vertical line z vertical line equals 1$ and $z not equal to 1$ , then all the values of $fraction numerator z over denominator 1 minus z to the power of 2 end exponent end fraction$ lie on

Therefore the correct option is choice 4

If $vertical line z vertical line equals 1$ and $z not equal to 1$ , then all the values of $fraction numerator z over denominator 1 minus z to the power of 2 end exponent end fraction$ lie on

Therefore the correct option is choice 4

If $z$ is a complex number such that $vertical line equals vertical line greater or equal than 2$ then the minimum value of $∣ z plus fraction numerator 1 over denominator 2 end fraction$ is is strictly

Therefore the correct option is choice 4

If $z$ is a complex number such that $vertical line equals vertical line greater or equal than 2$ then the minimum value of $∣ z plus fraction numerator 1 over denominator 2 end fraction$ is is strictly

Therefore the correct option is choice 4

parallel

If $open vertical bar fraction numerator z subscript 1 end subscript over denominator z subscript 2 end subscript end fraction close vertical bar equals 1$ and $a r g invisible function application open parentheses z subscript 1 end subscript z subscript 2 end subscript close parentheses equals 0$ then

Therefore the correct option is choice 3

If $open vertical bar fraction numerator z subscript 1 end subscript over denominator z subscript 2 end subscript end fraction close vertical bar equals 1$ and $a r g invisible function application open parentheses z subscript 1 end subscript z subscript 2 end subscript close parentheses equals 0$ then

Therefore the correct option is choice 3

One of the values of $open parentheses cis invisible function application fraction numerator pi over denominator 6 end fraction close parentheses to the power of fraction numerator 1 over denominator 2 end fraction end exponent plus open parentheses cis invisible function application fraction numerator negative pi over denominator 6 end fraction close parentheses to the power of fraction numerator 11 over denominator 2 end fraction end exponent$

One of the values of $open parentheses cis invisible function application fraction numerator pi over denominator 6 end fraction close parentheses to the power of fraction numerator 1 over denominator 2 end fraction end exponent plus open parentheses cis invisible function application fraction numerator negative pi over denominator 6 end fraction close parentheses to the power of fraction numerator 11 over denominator 2 end fraction end exponent$

If the distance between the points $left parenthesis a c o s invisible function application theta comma a s i n invisible function application theta right parenthesis$ , $left parenthesis a c o s invisible function application ϕ comma a s i n invisible function application ϕ right parenthesis$ is $2 a$
then $theta equals$ 6
Assertion (A): If $2 s i n invisible function application fraction numerator theta over denominator 2 end fraction equals square root of 1 plus s i n invisible function application theta end root plus square root of 1 minus s i n invisible function application theta end root$ , then $fraction numerator theta over denominator 2 end fraction$ lies between
$2 n pi plus fraction numerator pi over denominator 4 end fraction text and end text 2 n pi plus fraction numerator 3 pi over denominator 4 end fraction left parenthesis n element of z right parenthesis$
Reason $left parenthesis R right parenthesis colon$ If $fraction numerator theta over denominator 2 end fraction element of open parentheses fraction numerator pi over denominator 4 end fraction comma fraction numerator 3 pi over denominator 4 end fraction close parentheses$ , then $s i n invisible function application fraction numerator theta over denominator 2 end fraction greater than 0$

If the distance between the points $left parenthesis a c o s invisible function application theta comma a s i n invisible function application theta right parenthesis$ , $left parenthesis a c o s invisible function application ϕ comma a s i n invisible function application ϕ right parenthesis$ is $2 a$
then $theta equals$ 6
Assertion (A): If $2 s i n invisible function application fraction numerator theta over denominator 2 end fraction equals square root of 1 plus s i n invisible function application theta end root plus square root of 1 minus s i n invisible function application theta end root$ , then $fraction numerator theta over denominator 2 end fraction$ lies between
$2 n pi plus fraction numerator pi over denominator 4 end fraction text and end text 2 n pi plus fraction numerator 3 pi over denominator 4 end fraction left parenthesis n element of z right parenthesis$
Reason $left parenthesis R right parenthesis colon$ If $fraction numerator theta over denominator 2 end fraction element of open parentheses fraction numerator pi over denominator 4 end fraction comma fraction numerator 3 pi over denominator 4 end fraction close parentheses$ , then $s i n invisible function application fraction numerator theta over denominator 2 end fraction greater than 0$

parallel

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