Physics-
General
Easy

Question

When an AC source of emf E equals E subscript 0 end subscript s i n invisible function application left parenthesis 100 t right parenthesis is connected across a circuit, the phase difference between the E and the current i in the circuit is observed to be pi divided by 4 , as shown in the diagram. If the circuit consists possibly only of R-C or R-L or L-C series, find the relationship between the two elements.

  1. R equals 1 k capital omega comma C equals 10 mu F    
  2. R equals 1 k capital omega comma C equals 1 mu F    
  3. R equals 1 k capital omega comma L equals 10 H    
  4. R equals 1 k capital omega comma L equals 1 H    

The correct answer is: R equals 1 k capital omega comma C equals 10 mu F


    (i) here current lead the voltage
    table row cell t a n invisible function application ϕ equals fraction numerator R over denominator fraction numerator 1 over denominator omega c end fraction end fraction end cell row cell t a n invisible function application fraction numerator pi over denominator 4 end fraction equals R invisible function application omega C end cell end table
    R C equals fraction numerator 1 over denominator omega end fraction equals fraction numerator 1 over denominator 100 end fraction

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