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Easy

Question

Simplify each expressions and state the domain : fraction numerator x squared plus 2 x plus 1 over denominator x cubed minus 2 x squared minus 3 x end fraction

hintHint:

The expansions of some identities are:
left parenthesis x plus a right parenthesis squared equals x squared plus 2 a x plus a squared
left parenthesis x plus a right parenthesis left parenthesis x plus b right parenthesis equals x squared plus left parenthesis a plus b right parenthesis x plus a b
Domain is the set of input values of an expression.
We are asked to simplify the expression and find its domain.

The correct answer is: x (x - 3) = 0 x = 0 and x = 3


    Step 1 of 2:
    Simplify the numerator using the identity, left parenthesis x plus a right parenthesis squared equals x squared plus 2 a x plus a squared text . Thus, we get:  end text
    fraction numerator x squared plus 2 x plus 1 over denominator x cubed minus 2 x squared minus 3 x end fraction equals fraction numerator left parenthesis x plus 1 right parenthesis squared over denominator x cubed minus 2 x squared minus 3 x end fraction
    Now, simplify the denominator:
    fraction numerator left parenthesis x plus 1 right parenthesis squared over denominator x cubed minus 2 x squared minus 3 x end fraction equals fraction numerator left parenthesis x plus 1 right parenthesis squared over denominator x open parentheses x squared minus 2 x minus 3 close parentheses end fraction
    equals fraction numerator left parenthesis x plus 1 right parenthesis squared over denominator x open parentheses x squared minus 3 x plus x minus 3 close parentheses end fraction
    equals fraction numerator left parenthesis x plus 1 right parenthesis squared over denominator x left parenthesis x left parenthesis x minus 3 right parenthesis plus 1 left parenthesis x minus 3 right parenthesis right parenthesis end fraction
    equals fraction numerator left parenthesis x plus 1 right parenthesis squared over denominator x left parenthesis x plus 1 right parenthesis left parenthesis x minus 3 right parenthesis end fraction
    equals fraction numerator left parenthesis x plus 1 right parenthesis over denominator x left parenthesis x minus 3 right parenthesis end fraction
    Here, we took out the common x first and then we applied the identity,
                                             left parenthesis x plus a right parenthesis left parenthesis x plus b right parenthesis equals x squared plus left parenthesis a plus b right parenthesis x plus a b

    Thus, the simplified expression is: fraction numerator left parenthesis x plus 1 right parenthesis over denominator x left parenthesis x minus 3 right parenthesis end fraction
    Step 2 of 2:
    The denominator of the expression cannot be zero. Here, the denominator is: . It taken the value zero, when:
    x left parenthesis x minus 3 right parenthesis equals 0
    x equals 0 straight & x equals 3 to the power of straight prime
    .left parenthesis negative straight infinity comma 0 right parenthesis union left parenthesis 0 comma 3 right parenthesis union left parenthesis 3 comma straight infinity right parenthesis.

    There might be several values for which a denominator of a rational function may take zero.

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