Question
Simplify the following expression.

Hint:
The expansions of certain identities are:


We are asked to simplify the given expression
The correct answer is: the simplified expression is (x2 -x3 +4x +11)/(x+2)
Step 1 of 2:
Fins the LCM of the expression
,





Thus, the expression becomes
,
Step 2 of 2:
Now, find the product of 
For that, simplify and cancel out the common factors




Hence, the simplified expression is
;
LCM of two numbers or values are the least common multiples of both of them.
Related Questions to study
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Sketch the graph of 
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
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
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
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
The LCM of the polynomials
is.
The LCM of the polynomials
is.
Write the equation in slope-intercept form of the line that passes through the points (5, 4) and (-1, 6).
The slope intercept form is y = mx + b, where m represents the slope and b represents the y-intercept. We can draw the graph of a linear equation on the x-y coordinate plane using this form of a linear equation.
Steps for determining a line's equation from two points:
Step 1: The slope formula used to calculate the slope.
Step 2: To determine the y-intercept, use the slope and one of the points (b).
Step 3: Once you know the values for m and b, we can plug them into the slope-intercept form of a line, i.e., (y = mx + b), to obtain the line's equation.
Write the equation in slope-intercept form of the line that passes through the points (5, 4) and (-1, 6).
The slope intercept form is y = mx + b, where m represents the slope and b represents the y-intercept. We can draw the graph of a linear equation on the x-y coordinate plane using this form of a linear equation.
Steps for determining a line's equation from two points:
Step 1: The slope formula used to calculate the slope.
Step 2: To determine the y-intercept, use the slope and one of the points (b).
Step 3: Once you know the values for m and b, we can plug them into the slope-intercept form of a line, i.e., (y = mx + b), to obtain the line's equation.