Maths-
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Easy

Question

The slope of line a is – 4. Line b is perpendicular to line a. The equation of line c is 3y + 12x = 6. What is the relation between line b and line c?

hintHint:

y = m1x + c1 and y = m2x + c2 are considered are perpendicular lines if
m1m2 = -1

The correct answer is: line b and line c are perpendicular to each other. So, mc = –4


    It is given that the slope of line a is –4 and it is perpendicular to line b. Let the slope of line b is mb.

    so, –4  mb = –1

    mb =
    Line c is given as 3y + 12x = 6 ans its y = mx + c form is y = – 4x + 2
    Now, 1 fourth  (-4) = –1
    We can see that mb  mc = -1. So, line b and line c are perpendicular to each other.
    Final Answer:
    Hence, line b and line c are perpendicular to each other.
    So, mc = –4

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