Maths-
General
Easy
Question
What are all the possible values of b for which is it factorable using only integer coefficients and constant?
Hint:
to be factorable we need to write the middle term as a sum of factors of 1 st and last term.
The correct answer is: {-23,-10,-5,-2,2,5,10,23} are all possible values of b.
Ans:- {-23,-10,-5,-2,2,5,10,23} are all possible values of b.
Given, is it factorable so be must be sum of factors of (-8)(3)
Factors of -24 are
(1,-24) b can be -24 + 1 = -23
(2,-12) b can be -12 + 2 = -10
(3,-8) b can be -8 + 3 = -5
(4,-6) b can be 4 - 6 = -2
(6,-4) b can be 6 - 4 = 2
(8,-3) b can be 8 - 3 = 5
(12,-2) b can be 12 - 2 = 10
(24,-1) b can be 24 - 1 = 23
So, there are 8 possible values of b they are {-23, -10, -5, -2, 2, 5, 10, 23}
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