Maths-
General
Easy

Question

Which of the following pieces of data does not uniquely determine an acute angled triangle ABC (R being the radius of the circumcircle) -

  1. a, sin A, sin B
  2. a, b, c
  3. a, sin B, R
  4. a, sin A, R

hintHint:

Here we have to find the following data does not uniquely determine an acute angled triangle ABC. And also, R being the radius of the circumcircle. Here uses the sine law to find the solution.

The correct answer is: a, sin A, R


    Here we have to find the which is not uniquely determine an acute angled triangle.
    By sine law in ΔABC,
    we have
    fraction numerator a over denominator sin A end fraction = fraction numerator b over denominator sin B end fraction = c over sin(π−A−B) = 2R
    or
    fraction numerator a over denominator sin A end fraction = fraction numerator b over denominator sin B end fraction = c over sin(A+B) = 2R
    From option,
    (1) If we know a, sin A, sin B, we can find b, c, and the value of angle A, B, C
    (2) With a, b, c we can find ∠A, ∠B, ∠C using the cosine law.
    (3) a, sin B, R are given, so sin A, b and hence sin(A+B) sin(A+B) and then C be found
    (4) If we know a, sin A, R, then we can get the ratio b/sin B or c/sin(A+B) only. We cannot determine the values of b, c, sin B, sin C separately.
    Therefore, the triangle cannot be determined uniquely in this case.
    Therefore, the correct answer is a, sin A, R

    In this question, the which is not uniquely determine an acute angled triangle. If we know a, sin A , R, then we can get the ratio b/sin B or c/sin(A+B) only. We cannot determine the values of b, c, sin B, sin C separately.

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