Chemistry-
General
Easy

Question

Which of the following statement is incorrect?

  1. Pure aluminium oxide is obtained by heating aluminium hydroxide
  2. Cryolite lowers down the melting point of bauxite in electrolytic cell for extraction of aluminium

  3. Carbonate ores are converted into oxides by roasting ore in air

  4. Mercury cannot be produced by roasting the cinnabar ore in air

The correct answer is:

Carbonate ores are converted into oxides by roasting ore in air

Related Questions to study

General
Maths-

L t subscript left parenthesis x rightwards arrow 0 right parenthesis invisible function application 1 divided by s i n squared invisible function application x minus 1 divided by s i n h squared invisible function application x equals

L t subscript left parenthesis x rightwards arrow 0 right parenthesis invisible function application 1 divided by s i n squared invisible function application x minus 1 divided by s i n h squared invisible function application x equals

Maths-General
General
Chemistry-

Which of the following ore does NOT show the correct formula?

Which of the following ore does NOT show the correct formula?

Chemistry-General
General
Maths-

The quadratic equation whose roots are I and  where l equals l i m subscript left parenthesis theta rightwards arrow 0 right parenthesis   left parenthesis left parenthesis 3 s i n invisible function application theta minus 4 s i n cubed invisible function application theta right parenthesis divided by theta right parenthesis m equals l i m subscript left parenthesis theta rightwards arrow 0 right parenthesis   left parenthesis left parenthesis 2 t a n invisible function application theta right parenthesis divided by theta left parenthesis 1 minus t a n squared invisible function application theta right parenthesis right parenthesis

The quadratic equation whose roots are I and  where l equals l i m subscript left parenthesis theta rightwards arrow 0 right parenthesis   left parenthesis left parenthesis 3 s i n invisible function application theta minus 4 s i n cubed invisible function application theta right parenthesis divided by theta right parenthesis m equals l i m subscript left parenthesis theta rightwards arrow 0 right parenthesis   left parenthesis left parenthesis 2 t a n invisible function application theta right parenthesis divided by theta left parenthesis 1 minus t a n squared invisible function application theta right parenthesis right parenthesis

Maths-General
parallel
General
Chemistry-

In zone-refining method the molten zone

In zone-refining method the molten zone

Chemistry-General
General
Maths-

L t left parenthesis x rightwards arrow 0 right parenthesis equals left parenthesis t a n cubed invisible function application x minus s i n cubed invisible function application x right parenthesis divided by x cubed

L t left parenthesis x rightwards arrow 0 right parenthesis equals left parenthesis t a n cubed invisible function application x minus s i n cubed invisible function application x right parenthesis divided by x cubed

Maths-General
General
Maths-

Four newly  married couples are dancing at a function the selection of the partner is random. The number of ways that exactly one husband  is not dancing with his own wife is

Four newly  married couples are dancing at a function the selection of the partner is random. The number of ways that exactly one husband  is not dancing with his own wife is

Maths-General
parallel
General
Maths-

There are 12 intermediate stations on a railway line between 2 stations. The number  number of ways that a train can be made to stop at 4 of these intermediate stations no two of these halting stations being consecutive is

There are 12 intermediate stations on a railway line between 2 stations. The number  number of ways that a train can be made to stop at 4 of these intermediate stations no two of these halting stations being consecutive is

Maths-General
General
Maths-

The number of ways of forming an arrangement of 4 letters from the letters of the word "IITJEE" is

The number of ways of forming an arrangement of 4 letters from the letters of the word "IITJEE" is

Maths-General
General
Maths-

L t ┬ left parenthesis x rightwards arrow 0 right parenthesis equals left parenthesis s i n invisible function application left parenthesis pi c o s squared invisible function application x right parenthesis right parenthesis divided by x squared equal to

L t ┬ left parenthesis x rightwards arrow 0 right parenthesis equals left parenthesis s i n invisible function application left parenthesis pi c o s squared invisible function application x right parenthesis right parenthesis divided by x squared equal to

Maths-General
parallel
General
Maths-

L t subscript left parenthesis x plus 0 right parenthesis left parenthesis left parenthesis 1 minus c o s invisible function application 2 x right parenthesis left parenthesis 3 plus c o s invisible function application x right parenthesis right parenthesis divided by left parenthesis x t a n invisible function application 4 x right parenthesis
is equal to

L t subscript left parenthesis x plus 0 right parenthesis left parenthesis left parenthesis 1 minus c o s invisible function application 2 x right parenthesis left parenthesis 3 plus c o s invisible function application x right parenthesis right parenthesis divided by left parenthesis x t a n invisible function application 4 x right parenthesis
is equal to

Maths-General
General
Maths-

L t subscript left parenthesis x rightwards arrow 0 right parenthesis invisible function application left parenthesis t a n invisible function application x minus s i n invisible function application x right parenthesis divided by x squared equals

L t subscript left parenthesis x rightwards arrow 0 right parenthesis invisible function application left parenthesis t a n invisible function application x minus s i n invisible function application x right parenthesis divided by x squared equals

Maths-General
General
Maths-

L t subscript left parenthesis x rightwards arrow 8 right parenthesis invisible function application left parenthesis √ left parenthesis 1 plus √ left parenthesis 1 plus x right parenthesis right parenthesis minus 2 right parenthesis divided by left parenthesis x minus 8 right parenthesis equals

L t subscript left parenthesis x rightwards arrow 8 right parenthesis invisible function application left parenthesis √ left parenthesis 1 plus √ left parenthesis 1 plus x right parenthesis right parenthesis minus 2 right parenthesis divided by left parenthesis x minus 8 right parenthesis equals

Maths-General
parallel
General
Maths-

If a with ‾ on top equals 2 i with ‾ on top plus 3 j with ‾ on top plus k with ‾ on top comma a with ‾ on top cross times b with ‾ on top equals 7 i with ‾ on top minus 3 j with ‾ on top minus 5 k with ‾ on top comma a with ‾ on top times b with ‾ on top equals 1 then stack b with ‾ on top equals

For such questions, we should know how to find the dot product and cross product. Dot product of two vectors is always a scalar quantity. The cross product of two vectors is a vector quantity.

If a with ‾ on top equals 2 i with ‾ on top plus 3 j with ‾ on top plus k with ‾ on top comma a with ‾ on top cross times b with ‾ on top equals 7 i with ‾ on top minus 3 j with ‾ on top minus 5 k with ‾ on top comma a with ‾ on top times b with ‾ on top equals 1 then stack b with ‾ on top equals

Maths-General

For such questions, we should know how to find the dot product and cross product. Dot product of two vectors is always a scalar quantity. The cross product of two vectors is a vector quantity.

General
Maths-

If a with ‾ on top comma b with ‾ on top comma c with ‾ on top are non coplanar vectors then the roots of equation open square brackets table attributes columnalign left end attributes row cell stack b with ‾ on top cross times stack c with ‾ on top end cell cell stack c with ‾ on top cross times stack a with ‾ on top end cell cell stack a with ‾ on top cross times stack b with ‾ on top end cell end table close square brackets x to the power of 2 end exponent plus open square brackets table attributes columnalign left end attributes row cell stack a with ‾ on top plus stack b with ‾ on top end cell cell stack b with ‾ on top plus stack c with ‾ on top end cell cell stack c with ‾ on top plus stack a with ‾ on top end cell end table close square brackets x plus open square brackets table attributes columnalign left end attributes row cell stack b with ‾ on top minus stack c with ‾ on top end cell cell stack c with ‾ on top minus stack a with ‾ on top end cell cell stack a with ‾ on top minus stack b with ‾ on top end cell end table close square brackets plus 1 equals 0

If a with ‾ on top comma b with ‾ on top comma c with ‾ on top are non coplanar vectors then the roots of equation open square brackets table attributes columnalign left end attributes row cell stack b with ‾ on top cross times stack c with ‾ on top end cell cell stack c with ‾ on top cross times stack a with ‾ on top end cell cell stack a with ‾ on top cross times stack b with ‾ on top end cell end table close square brackets x to the power of 2 end exponent plus open square brackets table attributes columnalign left end attributes row cell stack a with ‾ on top plus stack b with ‾ on top end cell cell stack b with ‾ on top plus stack c with ‾ on top end cell cell stack c with ‾ on top plus stack a with ‾ on top end cell end table close square brackets x plus open square brackets table attributes columnalign left end attributes row cell stack b with ‾ on top minus stack c with ‾ on top end cell cell stack c with ‾ on top minus stack a with ‾ on top end cell cell stack a with ‾ on top minus stack b with ‾ on top end cell end table close square brackets plus 1 equals 0

Maths-General
General
Maths-

The point of intersection of the plane r with rightwards arrow on top times left parenthesis 3 i with ˆ on top minus 5 j with ˆ on top plus 2 k with ˆ on top right parenthesis equals 6 will the stright line passing through the origin and perpendicular to the plane 2 x minus y minus z equals 4 is

The point of intersection of the plane r with rightwards arrow on top times left parenthesis 3 i with ˆ on top minus 5 j with ˆ on top plus 2 k with ˆ on top right parenthesis equals 6 will the stright line passing through the origin and perpendicular to the plane 2 x minus y minus z equals 4 is

Maths-General
parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.