Chemistry-
General
Easy
Question
Which of the following compounds shows evidence of the strongest hydrogen bonding?
- Propane-1,2,3-triol
- Propane-1,2-diol
- Propan-1-ol
- Propan-2-0l
The correct answer is: Propane-1,2,3-triol
Related Questions to study
Chemistry-
The compound buta-I,2-diene has: [Hint: The structure of buta-I ,2-diene is 
The compound buta-I,2-diene has: [Hint: The structure of buta-I ,2-diene is
Chemistry-General
Chemistry-
The number of sigma and pi bonds in but-l-ene-3-yne are:
The number of sigma and pi bonds in but-l-ene-3-yne are:
Chemistry-General
Chemistry-
The C-H bond distance is the longest in:
The C-H bond distance is the longest in:
Chemistry-General
Chemistry-
An aqueous solution of a mixture of two inorganic salts, when treated with diluteHCl, gave aprecipitate (P) and a filtrate (Q). The precipitate P was found todissolve in hot water. The filtrate (Q) remained unchanged,whentreatedwithH2Sinadilute mineral acidmedium. However, it gave a precipitate(R)with H2S in an ammoniacal medium. The precipitate R gave acolored solution(S),whentreatedwithH2O2inan aqueous NaOH medium. The colored solution Scontains:
An aqueous solution of a mixture of two inorganic salts, when treated with diluteHCl, gave aprecipitate (P) and a filtrate (Q). The precipitate P was found todissolve in hot water. The filtrate (Q) remained unchanged,whentreatedwithH2Sinadilute mineral acidmedium. However, it gave a precipitate(R)with H2S in an ammoniacal medium. The precipitate R gave acolored solution(S),whentreatedwithH2O2inan aqueous NaOH medium. The colored solution Scontains:
Chemistry-General
Physics-
The part of a transistor which is most heavily doped to produce large number of majority charge carries is :
The part of a transistor which is most heavily doped to produce large number of majority charge carries is :
Physics-General
Physics-
The energy band gap is maximum in :
The energy band gap is maximum in :
Physics-General
Physics-
Statement-1 : A transistor amplifier in common emitter configuration has a low input impedence.
Statement-2 : The base to emitter region is forward biased.
Statement-1 : A transistor amplifier in common emitter configuration has a low input impedence.
Statement-2 : The base to emitter region is forward biased.
Physics-General
Physics-
The current flowing through the zener diode in fig. is-
The current flowing through the zener diode in fig. is-
Physics-General
Physics-
Consider the following statements 1 and 2 and identify the correct answer- 1] A zener diode is always connected in reverse bias. 2] The potential barrier of a P-N junction lies between 0.1 to 0.3 V approximately.
Consider the following statements 1 and 2 and identify the correct answer- 1] A zener diode is always connected in reverse bias. 2] The potential barrier of a P-N junction lies between 0.1 to 0.3 V approximately.
Physics-General
Maths-
Let ABC be a triangle with equations of the sides AB, BC and CA respectively x – 2 = 0, y – 5 = 0 and 5x + 2y –10 = 0. Then the orthocentre of the triangle lies on the line
Let ABC be a triangle with equations of the sides AB, BC and CA respectively x – 2 = 0, y – 5 = 0 and 5x + 2y –10 = 0. Then the orthocentre of the triangle lies on the line
Maths-General
Maths-
Circles x2 + y2 = 4 and x2 + y2 – 2x – 4y + 3 = 0
Circles x2 + y2 = 4 and x2 + y2 – 2x – 4y + 3 = 0
Maths-General
Maths-
The length of intercept on y– axis, by a circle whose diameter is the line joining the points (–4, 3) and (12, –1) is -
The length of intercept on y– axis, by a circle whose diameter is the line joining the points (–4, 3) and (12, –1) is -
Maths-General
Maths-
The number of common tangents that can be drawn to the circles x2 + y2 – 4x – 6y – 3 = 0 and x2 + y2 + 2x + 2y + 1 = 0 is
The number of common tangents that can be drawn to the circles x2 + y2 – 4x – 6y – 3 = 0 and x2 + y2 + 2x + 2y + 1 = 0 is
Maths-General
Maths-
Statement I : 
because
Statement II : 
and nCr = nCn r
Statement I : because
Statement II : and nCr = nCn r
Maths-General
Maths-
If Cr denotes the combinatorial coefficient in the expansion of (1 + x)n then (nN
Statement 1: 
because
Statement 2: Root mean square of n distinct real numbers is always greater than their arithmetic mean, n ≥ 2
If Cr denotes the combinatorial coefficient in the expansion of (1 + x)n then (nN
Statement 1: because
Statement 2: Root mean square of n distinct real numbers is always greater than their arithmetic mean, n ≥ 2
Maths-General
