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Maths-

General

Easy

Question

Let ABC be a triangle with equations of the sides AB, BC and CA respectively x – 2 = 0, y – 5 = 0 and 5x + 2y –10 = 0. Then the orthocentre of the triangle lies on the line

x – y = 0
3x – y =1
x – 2y = 1
none of these

The correct answer is: 3x – y =1

The given triangle is a right angled triangle. Hence the orthocentre is the vertex containing the right angle.
Þ orthocentre is (2, 5) which lies on the lines 3x-y = 1.
Hence (B) is the correct answer.

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