Mathematics
Grade-8
Easy

Question

3x + 5y = 27
-4x – y = -19

  1. 4, 5
  2. 5, 9
  3. 3, 4
  4. 1, 9

hintHint:

An equation has a constant, variable and an equal to sign. It has two sides LHS and RHS. A linear equation is equation in which the highest degree is 1. Here, we have to find the value of unknown value, by operating both sides with the same number so that the equation will be balanced.

The correct answer is: 4, 5


    In the question the given equations are,
    3x + 5y = 27           ...................(1)
    -4x – y = -19           ..................(2)
    Step 1: Multiply eq. 2 with 5.
    On multiplying eq. 2 with 5 we get,
    -20x - 5y= -95               .....................(3)
    Step 2: Add eq. 1 and eq. 3.
    On adding eq. 1 and eq. 3 we get,
    3x + 5y = 27
    (+)
    -20x - 5y= -95
    ---------------------
    -17x= -68
    ------------------------
    -17x= -68
    rightwards double arrow x equals space fraction numerator negative 68 over denominator negative 17 end fraction
rightwards double arrow x equals 4
    Step 3: Put the value of x in eq. 2.
    -4x -y = -19
    rightwards double arrow negative 4 cross times 4 space minus y equals space minus 19
rightwards double arrow negative 16 minus y equals space minus 19
rightwards double arrow negative y equals negative 19 plus 16
rightwards double arrow negative y equals negative 3
rightwards double arrow y equals 3
    So, the values of y and x are 3 and 4 respectively.

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

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