Mathematics
Grade5
Easy

Question

Add 2 over 3 and space 1 half.

  1. 1 half
  2. 3 over 2
  3. 5 over 3
  4. 7 over 6

hintHint:

In this question we have to add two fractions for that we have to make denominator same this can be done by taking LCM. LCM is the least common multiple of two integers. We will use the prime factorization method to find the LCM. In prime factorization method the simply put the factor of each number and then for LCM we take product of factors, but we consider the repeated factors only one time but with highest exponent.

The correct answer is: 7 over 6


    2 over 3 space equals space 4 over 6
1 half space equals space 3 over 6
4 over 6 space plus space 3 over 6 equals 7 over 6
    Step1: First we will write all the prime factors of the denominators
    In this question the denominators are 3 and 2.
    Factors of 2 are:2 to the power of 1
    Factors of 3 are:3 to the power of 1
    Step2:  For calculating the LCM we will multiply the factors by considering the common factors only one time with the highest exponent.
    In this case there is no common factor.
    LCM (3,2) = 2 to the power of 1 cross times 3 to the power of 1
    LCM (3,2) = 6

    Step3: Now what we do is divide the LCM by each denominator and multiply the numerator by quotient and then add them
    So, 6 over 2 space equals space 3
    and 6 over 3 space equals space 2
    So, we will multiply the numerator of 2 by 3 and numerator of 3 by 2.
    fraction numerator 2 cross times 2 plus 1 cross times 3 over denominator 6 end fraction space equals 7 over 6
    So, the sum of 2 over 3 and 1 half is 7 over 6.

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