Mathematics
Grade-8
Easy

Question

-4x – 5y = -1
-2x – 5y = 7

  1. 4, -3
  2. 8, 0
  3. 1, 2
  4. -4, -3

hintHint:

  1. The Linear Combination Method , aka The Addition Method , aka The Elimination Method. Add (or subtract) a multiple of one equation to (or from) the other equation, in such a way that either the x-terms or the y -terms cancel out. Then solve for x (or y , whichever's left) and substitute back to get the other coordinate.

The correct answer is: 4, -3


    bold italic U bold italic s bold italic i bold italic n bold italic g bold space bold italic E bold italic l bold italic i bold italic m bold italic i bold italic n bold italic a bold italic t bold italic i bold italic o bold italic n bold space bold italic m bold italic e bold italic t bold italic h bold italic o bold italic d
minus 4 x space – space 5 y space equals space minus 1 space c a n space a l s o space b e space w r i t t e n space a s space 4 x plus 5 y space equals space 1 space space space space space......... space space space space left parenthesis a right parenthesis
minus 2 x space – space 5 y space equals space 7 space c a n space a l s o space b e space w r i t t e n space a s space 2 space x plus 5 y space equals negative 7 space space space space space space.......... space space space left parenthesis b right parenthesis
bold italic M bold italic u bold italic l bold italic t bold italic i bold italic p bold italic l bold italic y bold italic i bold italic n bold italic g bold space bold 2 bold space bold italic o bold italic n bold space bold italic E bold italic q bold italic u bold italic a bold italic t bold italic i bold italic o bold italic n bold space bold left parenthesis bold italic b bold right parenthesis
comma 2 space cross times left parenthesis 2 x plus 5 y space equals negative 7 right parenthesis space equals space 4 x space plus space 10 y space equals negative 14 space space space space space............ left parenthesis c right parenthesis
bold italic S bold italic u bold italic b bold italic t bold italic r bold italic a bold italic c bold italic t bold italic i bold italic n bold italic g bold space bold italic e bold italic q bold italic u bold italic a bold italic t bold italic i bold italic o bold italic n bold space bold left parenthesis bold italic a bold right parenthesis bold space bold italic a bold italic n bold italic d bold space bold left parenthesis bold italic c bold right parenthesis bold space
space space space space space 4 x space plus space 5 y space equals space 1
minus space space space space space space space space space
space space space space space space space 4 x space plus space 10 y space equals space minus 14 space space space space
space space _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
equals space space space space space space 0 space minus space 5 y space equals space 15
equals space space space space space space space space space y space equals space minus 3
bold italic S bold italic u bold italic b bold italic s bold italic t bold italic i bold italic t bold italic u bold italic t bold italic e bold space bold italic v bold italic a bold italic l bold italic u bold italic e bold space bold italic o bold italic f bold space bold italic y bold space bold italic i bold italic n bold space bold italic a bold italic n bold italic y bold space bold italic e bold italic q bold italic u bold italic a bold italic t bold italic i bold italic o bold italic n bold space bold italic e bold italic i bold italic t bold italic h bold italic e bold italic r bold space bold left parenthesis bold italic a bold right parenthesis bold space bold italic o bold italic r bold space bold left parenthesis bold italic b bold right parenthesis
w e space g e t space x space equals space 4
bold italic T bold italic h bold italic u bold italic s bold space bold comma bold left parenthesis bold italic x bold comma bold italic y bold right parenthesis bold space bold equals bold space bold left parenthesis bold 4 bold comma bold minus bold 3 bold right parenthesis

    Related Questions to study

    Grade-8
    Mathematics

    -2x – 5y = 10
    -x – y = -1

    -2x – 5y = 10
    -x – y = -1

    MathematicsGrade-8
    Grade-8
    Mathematics

    -5x + y = -3
    5x – 4y = 12

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    -5x + y = -3
    5x – 4y = 12

    MathematicsGrade-8

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    Grade-8
    Mathematics

    4x - 4y = 16
    2x + y = -1

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    4x - 4y = 16
    2x + y = -1

    MathematicsGrade-8

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    parallel
    Grade-8
    Mathematics

    2x + y = -5
    -4x + y = -5

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    2x + y = -5
    -4x + y = -5

    MathematicsGrade-8

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    Grade-8
    Mathematics

    3x + 4y = 2
    -4x + 3y = -11

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    3x + 4y = 2
    -4x + 3y = -11

    MathematicsGrade-8

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    Grade-8
    Mathematics

    -2x + y = 11
    x = -3

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In substitution method value of one variable is substituted an equation in order to get the value of that variable. After finding the value of one variable we can put that value in one equation to find the value of another variable.

    -2x + y = 11
    x = -3

    MathematicsGrade-8

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In substitution method value of one variable is substituted an equation in order to get the value of that variable. After finding the value of one variable we can put that value in one equation to find the value of another variable.

    parallel
    Grade-8
    Mathematics

    -5x – 2y = 6
    x + 4y = 6

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    -5x – 2y = 6
    x + 4y = 6

    MathematicsGrade-8

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    Grade-8
    Mathematics

    x – 2y = -13
    x + 4y = 11

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    x – 2y = -13
    x + 4y = 11

    MathematicsGrade-8

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    Grade-8
    Mathematics

    3x + 5y = 27
    -4x – y = -19

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    3x + 5y = 27
    -4x – y = -19

    MathematicsGrade-8

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    parallel
    Grade-8
    Mathematics

    5x + 2y = -13
    -x – 2y = 1

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    5x + 2y = -13
    -x – 2y = 1

    MathematicsGrade-8

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    Grade-8
    Mathematics

    x – 2y = 7
    -2x + y = 1

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    x – 2y = 7
    -2x + y = 1

    MathematicsGrade-8

    We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.

    Grade-8
    Mathematics

    According to the row relative frequency table, find the percent of girls polled who prefer cats as their pet.

    Percent is referred as per hundred which means the ratio of given number and 100. Percent can be calculated by using the formula fraction numerator v a l u e over denominator t o t a l space v a l u e end fraction cross times 100.

    According to the row relative frequency table, find the percent of girls polled who prefer cats as their pet.

    MathematicsGrade-8

    Percent is referred as per hundred which means the ratio of given number and 100. Percent can be calculated by using the formula fraction numerator v a l u e over denominator t o t a l space v a l u e end fraction cross times 100.

    parallel
    Grade-8
    Mathematics

    A survey explored the relationship between gender and band class. Identify a reasonable conclusion among the following.

    Conclusion of the data given in the table can be derived from the information provided in the table.

    A survey explored the relationship between gender and band class. Identify a reasonable conclusion among the following.

    MathematicsGrade-8

    Conclusion of the data given in the table can be derived from the information provided in the table.

    Grade-8
    Mathematics

    According to the two-way table, a person who does not play an instrument is most likely

    According to the two-way table, a person who does not play an instrument is most likely

    MathematicsGrade-8
    Grade-8
    Mathematics

    According to the column relative frequency table, find the relative frequency of girls that have red hair.

    Relative frequency represents the number of times an event has occurred. It can be determined using the formula fraction numerator f r e q u e n c y over denominator s u m space o f space a l l space f r e q u e n c i e s end fraction.

    According to the column relative frequency table, find the relative frequency of girls that have red hair.

    MathematicsGrade-8

    Relative frequency represents the number of times an event has occurred. It can be determined using the formula fraction numerator f r e q u e n c y over denominator s u m space o f space a l l space f r e q u e n c i e s end fraction.

    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.