Mathematics
Grade9
Easy

Question

If TV=16 and UV=21,  SV=?

  1. 16
  2. 12.19
  3. 2.4
  4. 25.12

hintHint:

We are given a right-angled triangle STU. An altitude is drawn from the vertex having the right angle. It divides the base of the triangle into two parts. The values of parts are given. We are asked to find the value of the SV. To solve this question, we will use the properties of a right-angled triangle.

The correct answer is: 12.19


    The point where altitude meets be “V”
    From the figure, we can write the values of lengths and angles.
    Length of TV = 16
    Length of UV = 21
    Angle STU = 90°
    Let the value of SV be “b”
    Due to the altitude, two right-angled triangles are formed.
    There is a theorem for altitude drawn from the right angle of a right-angled triangle. It states that, “When altitude is drawn from a right angle, two similar triangles are formed. They are similar to each other. They are also similar to the parent triangle”.
    ∆SVT ~ ∆TVU
    So, the ratio of their sides will be equal.
    fraction numerator S V over denominator T V end fraction equals fraction numerator T V over denominator U V end fraction
b over 16 equals 16 over 21
b space equals space fraction numerator 16 space cross times space 16 over denominator 21 end fraction
b space equals space 12.19
    Therefore, the value of SV is 12.19

    To solve such questions, we should know the properties of right-angled triangles and similar triangles. To find the altitude, we can just remember that the square of the altitude is equal to product of the two values

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