Mathematics
Grade9
Easy

Question

If JK=11 and JL=13,  JM =?

  1. 18
  2. 9.31
  3. 2.4
  4. 25.12

hintHint:

We are given a right-angled triangle JKL. An altitude is drawn from the vertex having the right angle. It divides the base of the triangle into two parts. The values of parts are given. We are asked to find the value of the JM. To solve this question, we will use the properties of a right-angled triangle.

The correct answer is: 9.31


    Let the point where altitude meets be “M”
    From the figure, we can write the values of lengths and angles.
    Length of JK = 11
    Length of JL = 13
    Angle JKL = 90°
    Consider the right-angled triangle JKL
    Let the ∠KJL be “A”
    Using the properties of right-angled triangle. ..
    ....C o s A space equals fraction numerator a d j a c e n t space s i d e over denominator h y p o t e n u s e end fraction
space space space space space space space space space space space equals fraction numerator J K over denominator J L end fraction
space space space space space space space space space space space equals 11 over 13
 
     Now consider the right-angled ∆KMJ.
    We have the value of ∠KJM
    Using the properties of right-angled triangle.
    C o s A space equals fraction numerator A d j a c e n t space s i d e over denominator H y p o t e n u s e end fraction
C o s A space equals fraction numerator J M over denominator 11 end fraction
S u b s t i t u t i n g space t h e space v a l u e space o f space C o s A
11 over 23 equals fraction numerator J M over denominator 11 end fraction
J M space equals fraction numerator 11 space cross times 11 over denominator 23 end fraction
J M space equals space 9.31
    Therefore, the value of JM is 9.31.

    Another method to solve this is using properties of similar triangles.

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