What will be the new position of the given point (8, 3) after translation of 3 units left and 2 units up?

Graph a quadrilateral whose vertices are A(-3, -2), B(-5, -2), C(-6, 1), and D(-3, 2). Graph ABCD quadrilateral and its image when rotated 180^o about the origin

Graph a quadrilateral whose vertices are A(-3, -2), B(-5, -2), C(-6, 1), and D(-3, 2). Graph ABCD quadrilateral and its image when rotated 90^o about the origin

Graph a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0). Rotate the triangle 270^o about the origin.

Graph a triangle LMN with vertices L(-5, -3), M(-3, -5), and N(0, -1). Rotate the triangle 180^o about the origin.

Find the image coordinate of the figure w.r.t 270^o rotation about the origin.

Find the image vertices of the line w.r.t 90^o rotation about the origin.

Find the coordinate of the point and its image point w.r.t 180^o rotation about the origin.

When a point (2, -4) is rotated counterclockwise about the origin. Find the coordinate after the rotation of 90^o rotation.

If you can rotate a figure more than 360^o, then the effect is the __________as rotating the figure by the angle minus 360^o.

Graph a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0). Rotate the triangle 180^o about the origin.

Given, the vertices of a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0).
For a rotation of 180 degrees, coordinate rule (a, b) → (-a, -b).
A(2, 1) → A’(-2, -1)
B(4, 4) → B’(-4, -4)
C(8, 0) → C’(-8, 0)
Now, graph the triangle A’B’C’.

Graph a triangle LMN with vertices L(-5, -3), M(-3, -5), and N(0, -1). Rotate the triangle 90 about the origin.

Given, the vertices of a triangle ABC with vertices L(-5, -3), M(-3, -5), and N(0, -1).
For a rotation of 90 degrees, coordinate rule (a, b) → (-b, a).
L(-5, -3) → L’(3, -5)
M(-3, -5) → M’(5, -3)
N(0, -1) → N’(1, 0)
Now, graph the triangle L’M’N’.

Find the image coordinates of the figure w.r.t 180^o rotation about the origin.

Given coordinates of the figure, A(1, 2), B(5, 2), and C(3, 5).
For a rotation of 180 degrees, coordinate rule (a, b) → (-a, -b).
A(1, 2) → A’(-1, -2)
B(5, 2) → B’(-5, -2)
C(3, 5) → C’(-3, -5)
Image coordinates of the figure are A’(-1, -2), B’(-5, -2), and C’(-3, -5).

Find the image vertices of the line w.r.t 90^o rotation about the origin.

Coordinate of the line AB, A= (1, 2) and B= (5, 2)
For a rotation of 90, coordinate rule (a, b) → (-b, a).
A(1, 2) → A’(-2, 1)
B(5, 2) → B’(-2, 5)
Image vertices of the line AB are A’(-2, 1) and B’(-2, 5).

Find the coordinate of the point and its image point w.r.t 270^o rotation about the origin.

Coordinate of point V = (-3, -2)
For a rotation of 270 degrees, coordinate rule (a, b) → (b, -a).
V(-3, -2) →  V’(-2, 3)
The coordinate V(-3, -2) and its image V’(-2, 3).

When a point (9, -2) is rotated counterclockwise about the origin. Find the coordinate after the rotation of 270^o rotation.

For a rotation of 270 degrees, (a, b) → (b, -a)
(9, -2) →(-2, -9)