Question
y = x2 – 4x + 4
y = 4 – x
If the ordered pair (x, y) satisfies the system of equations above, what is one possible value of x ?
The correct answer is: x = 0 or x = 5
HINT – Put value of y from one equation to other and then solve for x
SOLUTION – The given equations are
y = x2 – 4x + 4 ---- (1)
and y = 4 – x
Put y = 4 – x in equation (1),
We get , 4 – x = x2 – 4x + 4
0 = x2 – 4x – x
0 = x2 – 5x
0 = x ( x – 5)
x = 0 or x = 5
So, possible values of x are 0 and 5.
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