Maths-
General
Easy

Question

In the xy-plane, line l has a slope of 2. Line k is perpendicular to line l and contains the point (4, 2). Which of the following is an equation of line k ?

  1. y equals negative 2 x minus 6    
  2. y equals negative 2 x plus 10    
  3. y equals negative fraction numerator 1 over denominator 2 end fraction x    
  4. y equals negative fraction numerator 1 over denominator 2 end fraction x plus 4    

The correct answer is: y equals negative fraction numerator 1 over denominator 2 end fraction x plus 4


    The equation of a straight line in xy-plane is y = mx + c, where c is a constant and m is the slope of the straight line with coordinate (x, y).
    The slope of the perpendicular to the above said straight line is given by, m subscript perpendicular end subscript equals negative fraction numerator 1 over denominator m end fraction.
    Explanation:
    Step 1 of 2:
    We have slope of line l, m subscript l end subscript equals 2.
    Since line k is perpendicular to line l, then slope of line k is, m subscript k end subscript equals negative fraction numerator 1 over denominator 2 end fraction.
    Now, for the point (4, 2), we substitute the value in the straight line equation and we get,
    2 equals 4 cross times open parentheses negative fraction numerator 1 over denominator 2 end fraction close parentheses plus c
    ⇒ c = 2 + 2 = 4
    Step 2 of 2:
    Again, substituting the value of constant in the straight line equation, we get
    y equals negative fraction numerator 1 over denominator 2 end fraction x plus 4
    Final Answer:
    The right option is— y equals negative fraction numerator 1 over denominator 2 end fraction x plus 4.

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