Which of the following values is a solution to the equation above?

The correct answer is:

Hint: 
Concept used in the question is of the quadratic equation.
Quadratic equation has two solutions.
In quadratic equation is D (Discriminant) is given by b² - 4ac.
If D = 0, then equation have equal roots.
D > 0 then, equation has two real roots.
D < 0 then, equation has imaginary roots
Roots of quadratic equation are given by  where D is discriminant.
Step by step explanation:
Given:
Equation - 4v² + 6v + 1 = 0
Step 1:
Find Discriminant i. e D
D = b² - 4ac
⇒ D = 6² - 4(4)(1)
⇒ D = 36 - 16
⇒ D = 20
As the D > 0 therefore equation has real roots.
Step 2:
We know that,
Roots of quadratic equation are given by,

So, according to given information,
b= 6, D = 20 and a = 4


Step 3:
Now, take both roots separately,



Hence, the roots of above equation are .