Maths-
General
Easy
Question
A gas in an open container is heated from 27°C to 127°C. The fraction of the original amount of gas remaining in the container will b
Hint:
A gas is heated in open container. It is heated between two temperatures. We have to find the original fraction of gas left behind when it's heated. We will use the ideal gas equation and find the constant and variable values.
The correct answer is:
The ideal gas equation is PV = nRT
As the gas is heated in an open container, it's pressure is constant. The volume of the container is constant too. R is a constant.
n is number of moles and T is temperature. n denotes the amount of gas.
So, the above equation is nT = constant.
So, the temperature is inversely proportional to the gas.
The temperature they are heated from his 27°C to 127°C.
Let n1 be the original amount of gas and T1 be temperature at that time.
Let n2 be the amount of gas left after its heated. T2 is the temperature at that time.
We will write the temperature in Kelvin.
T1 = 27 + 273 = 300K
T2 = 127 + 273 = 400k
We know that nT= constant
So, we can write
n2T2 = n1T1
Dividing both the sides by T2
It means fraction of orginal amount is left.
For such questions, we should know idea gas equation. We have to be careful about constant and variable values. And we always have to convert the temperature into Kelvin. To convert the temperature in °C into Kelvin, we add 273 to it.
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