A student says that the expansion of the expression $left parenthesis negative 4 y plus z right parenthesis to the power of 7$ has seven terms. Describe and correct the error the student may have made ?

The answer can be also found using the Pascal’s triangle. For an expression (x + y)n , we would consider the (n+1)th row.

Use Pascal’s triangle and the binomial theorem to expand (x + 1)⁴ . Justify your work.

We can use both the binomial theorem and the Pascal’s triangle to get the expansion of any expression.

Use Pascal’s triangle and the binomial theorem to expand (x + 1)⁴ . Justify your work.

We can use both the binomial theorem and the Pascal’s triangle to get the expansion of any expression.

Emma factored $open parentheses 625 g to the power of 16 minus 25 h to the power of 4 close parentheses$ Describe and correct the error Emma made in factoring the polynomial.

It is important to recall the law of exponents while to expand polynomial expressions.

Emma factored $open parentheses 625 g to the power of 16 minus 25 h to the power of 4 close parentheses$ Describe and correct the error Emma made in factoring the polynomial.

It is important to recall the law of exponents while to expand polynomial expressions.

Expand $left parenthesis 3 x plus 4 y right parenthesis cubed$ using binomial theorem.

The answer can be found using the Pascal’s triangle. For $left parenthesis x plus y right parenthesis to the power of n$ , we would consider the (n+1)th row as the coefficients.

Expand $left parenthesis 3 x plus 4 y right parenthesis cubed$ using binomial theorem.

The answer can be found using the Pascal’s triangle. For $left parenthesis x plus y right parenthesis to the power of n$ , we would consider the (n+1)th row as the coefficients.

Expand $left parenthesis 3 x plus 4 y right parenthesis cubed$ using Pascal’s triangle.

The answer can be found using the binomial theorem $left parenthesis x plus y right parenthesis to the power of n equals sum from k equals 0 to n of n C subscript k x to the power of n minus k end exponent y to the power of k text where end text n greater or equal than 0$

Expand $left parenthesis 3 x plus 4 y right parenthesis cubed$ using Pascal’s triangle.

Use binomial theorem to expand expression (x + y)⁷ .

The answer can be found using the Pascal’s triangle. For an expression (x + y)n , we would have n + 1 term.

Use binomial theorem to expand expression (x + y)⁷ .

The answer can be found using the Pascal’s triangle. For an expression (x + y)n , we would have n + 1 term.

Use binomial theorem to expand expression (d - 1)⁴

The answer can be found using the Pascal’s triangle. For an expression $left parenthesis x plus y right parenthesis to the power of n$ , we would have n+ 1 term.

Use binomial theorem to expand expression (d - 1)⁴

The answer can be found using the Pascal’s triangle. For an expression $left parenthesis x plus y right parenthesis to the power of n$ , we would have n+ 1 term.

Use Pascal triangle to expand the expression (a - b)⁶ .

The answer can be found using the binomial expansion of $left parenthesis x plus y right parenthesis to the power of n equals sum from k equals 0 to n of n C subscript k x to the power of n minus k end exponent y to the power of k text where end text n greater or equal than 0$

Use Pascal triangle to expand the expression (a - b)⁶ .

Use Pascal’s triangle to expand the expression (x + 1)⁵

How many terms will there be in the expansion of the expression $left parenthesis x plus 3 right parenthesis to the power of n$ . Explain how you know?

Find the third term of the binomial expansion $left parenthesis a minus 3 right parenthesis to the power of 6$

The expansion of (x + y)n has n+1 terms while expanding. The answer can be found using the Pascal’s triangle or binomial expansion.

Find the third term of the binomial expansion $left parenthesis a minus 3 right parenthesis to the power of 6$

The expansion of (x + y)n has n+1 terms while expanding. The answer can be found using the Pascal’s triangle or binomial expansion.

Chemistry-

Factor $open parentheses x cubed minus 125 y to the power of 6 close parentheses$ in the form $left parenthesis x minus a right parenthesis open parentheses x squared plus b x plus c close parentheses$ . Then find the value of a,b and c.

Chemistry-General

Find the fifth term of the binomial expansion $left parenthesis x plus y right parenthesis to the power of 5$

The expansion of $left parenthesis x plus y right parenthesis to the power of n$ has n+1 terms while expanding. The answer can be found using the Pascal’s triangle or binomial expansion.

Find the fifth term of the binomial expansion $left parenthesis x plus y right parenthesis to the power of 5$

The expansion of $left parenthesis x plus y right parenthesis to the power of n$ has n+1 terms while expanding. The answer can be found using the Pascal’s triangle or binomial expansion.

The sum of the coefficients in the expansion of the expression $left parenthesis a plus b right parenthesis to the power of n$ is 64. Use Pascal’s triangle to find the value of n.

Using Pascal's Triangle, where n can be any positive integer as x and y are real numbers, one can determine the binomial coefficients of the terms of the binomial formula (x + y)ⁿ. Pascal Triangle is a type of number pattern that appears as a triangular arrangement and is represented by triangles. It starts with '1' at the top and continues with '1' on the triangle's two sides. Each new number in the Pascal triangle has equal values to the sum of the two integers above and below. The probability conditions in which this triangle is utilized vary. Every row represents this table's coefficient of expansion of (x + y)ⁿ. Zero row n = 0, (x + y)⁰

The sum of the coefficients in the expansion of the expression $left parenthesis a plus b right parenthesis to the power of n$ is 64. Use Pascal’s triangle to find the value of n.