Maths-
General
Easy

Question

Use Pascal’s triangle and the binomial theorem to expand (x + 1)4 . Justify your work.

hintHint:

Pascal's Triangle is a method to know the binomial coefficients of terms of binomial expression (x + y)n , where n can be any positive integer and x, y are real numbers. Pascal Triangle is represented in a triangular form, it is kind of a number pattern in the form of a triangular arrangement.
The binomial expansion is left parenthesis x plus y right parenthesis to the power of n equals sum from k equals 0 to n of   n C subscript k x to the power of n minus k end exponent y to the power of k comma text  here  end text n greater or equal than 0 .
We are asked to find expansion of the expression using Pascal’s triangle and binomial theorem

The correct answer is: Pascal’s triangle


     Step 1 of 3:
    The given expression is left parenthesis x plus 1 right parenthesis to the power of 4 . Here n=4. Thus, we would have 4+1=5 terms in the expansion. Here, x equals x space straight & space y equals 1.
    Step 2 of 3:
    Find the fifth row of the Pascal’s triangle to get the coefficients of left parenthesis x plus 1 right parenthesis to the power of 4 .


    Thus, the expansion is:

    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell left parenthesis x plus 1 right parenthesis to the power of 4 equals x to the power of 4 plus 4 x cubed left parenthesis 1 right parenthesis plus 6 x squared left parenthesis 1 right parenthesis squared plus 4 x left parenthesis 1 right parenthesis cubed plus 1 to the power of 4 end cell row cell equals x to the power of 4 plus 4 x cubed plus 6 x squared plus 4 x plus 1 end cell end table
    Hence, the expansion is; left parenthesis x plus 1 right parenthesis to the power of 4 equals x to the power of 4 plus 4 x cubed plus 6 x squared plus 4 x plus 1
    Step 3 of 3:
    Substitute the values of left parenthesis x plus 1 right parenthesis to the power of 4 in the binomial expansion to get the terms. Thus, we have:

    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell left parenthesis x plus 1 right parenthesis to the power of 4 equals 4 C subscript 0 x to the power of 4 plus 4 C subscript 1 x cubed left parenthesis 1 right parenthesis plus 4 C subscript 2 x squared left parenthesis 1 right parenthesis squared plus 4 C subscript 3 x left parenthesis 1 right parenthesis cubed plus 4 C subscript 4 4 to the power of 4 end cell row cell equals 1 x to the power of 4 plus 4 x cubed plus 6 x squared plus 4 x plus 1 end cell end table
    Thus, the expansion is; left parenthesis x plus 1 right parenthesis to the power of 4 equals x to the power of 4 plus 4 x cubed plus 6 x squared plus 4 x plus 1.
    The answer obtained using binomial theorem and Pascal’s triangle are the same. We can use both methods to find the answer.

    We can use both the binomial theorem and the Pascal’s triangle to get the expansion of any expression.

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