Find the axis of symmetry, vertex and y-intercept of the function
f(x) = 5x² + 5x + 12

The correct answer is: 12

This quadratic function is in standard form, f(x)=ax²+bx+c.
For every quadratic function in standard form the axis of symmetry is given by the formula x=−b/2a.
In f(x)= 5x² + 5x + 12 , a= 5, b= 5, and c= 12. So, the equation for the axis of symmetry is given by

x = −(5)/2(5)

x = -5/10

x = -1/2 = -0.5
The equation of the axis of symmetry for f(x)= 5x² + 5x + 12 is x = -0.5.
The x coordinate of the vertex is the same:

h = -0.5
The y coordinate of the vertex is :

k = f(h)

k = 5(h)² + 5h + 12

k = 5(-0.5)² + 5(-0.5) + 12

k = 1.25 – 2.5 + 12

k = 10.75
Therefore, the vertex is (-0.5 , 10.75)
For finding the y- intercept we firstly rewrite the equation by substituting 0 for x.

y = 5(0)² + 5(0) + 12

y = 0 + 0 + 12

y = 12
Therefore, Axis of symmetry is x = -0.5
Vertex is ( -0.5 , 10.75)
Y- intercept is 12.