Find the axis of symmetry, vertex and y-intercept of the function
f(x) = x² - 6x + 12

The correct answer is: 12

This quadratic function is in standard form, f(x)=ax²+bx+c.
For every quadratic function in standard form the axis of symmetry is given by the formula x=−b/2a.
In f(x)= x² - 6x + 12,  a= 1, b= -6, and c= 12. So, the equation for the axis of symmetry is given by

x = −(-6)/2(1)

x = 6/2

x = 3
The equation of the axis of symmetry for f(x)= x² - 6x + 12 is x = 3.
The x coordinate of the vertex is the same:

h = 3
The y coordinate of the vertex is :

k = f(h)

k = h² – 6h + 12

k = (3)² - 6(3) + 12

k = 9 – 18 + 12

k = 3
Therefore, the vertex is (3 , 3)
For finding the y- intercept we firstly rewrite the equation by substituting 0 for x.

y = (0)² - 6(0) + 12

y = 0 + 0 + 12

y = 12
Therefore, Axis of symmetry is x = 3
Vertex is (3 , 3)
Y- intercept is 12.