Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

The number of ways to give 16 different things to three persons A, B, C so that B gets 1 more than A and C gets 2 more than B, is -

$\frac{16!}{4! 5! 7!}$
4! 5! 7!
$\frac{16!}{3! 5! 8!}$
3! 5! 8!

The correct answer is: $fraction numerator 16 factorial over denominator 4 factorial 5 factorial 7 factorial end fraction$

No. of things given to A is 4
No. of things given to B is 5
No. of things given to C is 7
No. of ways = $fraction numerator 16 factorial over denominator 4 factorial 5 factorial 7 factorial end fraction$

Related Questions to study

A determinant of second order is made with the element 0 and 1. The number of determinants with non negative values is –

A determinant of second order is made with the element 0 and 1. The number of determinants with non negative values is –

A five letter word is to be formed such that the letters appearing in the odd numbered positions are taken from the letters which appear without repetition in the word 'MATHEMATICS'. Further the letters appearing in the even numbered positions are taken from the letters which appear with repetitions in the same word MATHEMATICS. In how many different ways the five letter word can be formed -

A five letter word is to be formed such that the letters appearing in the odd numbered positions are taken from the letters which appear without repetition in the word 'MATHEMATICS'. Further the letters appearing in the even numbered positions are taken from the letters which appear with repetitions in the same word MATHEMATICS. In how many different ways the five letter word can be formed -

In how many ways can we decide batting order of Indian cricket team such that Tendulkar will always bat before Dhoni and Dhoni before Yuvraj and Yuvraj will never be the last person to bat

In how many ways can we decide batting order of Indian cricket team such that Tendulkar will always bat before Dhoni and Dhoni before Yuvraj and Yuvraj will never be the last person to bat

parallel

6 letters are to be posted in three letter boxes. The number of ways of posting the letters when no letter box remains empty is

6 letters are to be posted in three letter boxes. The number of ways of posting the letters when no letter box remains empty is

Sum of all divisors of 5400 whose unit digit is 0, is

Sum of all divisors of 5400 whose unit digit is 0, is

If $cos invisible function application theta equals 1 half open parentheses a plus 1 over a close parentheses$ then $cos invisible function application 3 theta$ in terms of ‘a’ =

If $cos invisible function application theta equals 1 half open parentheses a plus 1 over a close parentheses$ then $cos invisible function application 3 theta$ in terms of ‘a’ =

parallel

Exact value of $cos invisible function application 20 to the power of ring operator plus 2 sin squared invisible function application 55 to the power of ring operator minus sin invisible function application 65 to the power of ring operator$ is -

Exact value of $cos invisible function application 20 to the power of ring operator plus 2 sin squared invisible function application 55 to the power of ring operator minus sin invisible function application 65 to the power of ring operator$ is -

If $fraction numerator sin invisible function application 2 alpha minus sin invisible function application 3 alpha plus sin invisible function application 4 alpha over denominator cos invisible function application 2 alpha minus cos invisible function application 3 alpha plus cos invisible function application 4 alpha end fraction equals tan invisible function application k alpha$ is an identity then the value of k is equal to -

If $fraction numerator sin invisible function application 2 alpha minus sin invisible function application 3 alpha plus sin invisible function application 4 alpha over denominator cos invisible function application 2 alpha minus cos invisible function application 3 alpha plus cos invisible function application 4 alpha end fraction equals tan invisible function application k alpha$ is an identity then the value of k is equal to -

If $tan invisible function application theta equals square root of a over b end root$ where a, b are positive reals then the value of $space sin invisible function application theta sec 7 theta plus cos invisible function application theta cosec to the power of blank 7 theta$ is -

If $tan invisible function application theta equals square root of a over b end root$ where a, b are positive reals then the value of $space sin invisible function application theta sec 7 theta plus cos invisible function application theta cosec to the power of blank 7 theta$ is -

parallel

The expression $fraction numerator sin invisible function application 22 to the power of ring operator cos invisible function application 8 to the power of ring operator plus cos invisible function application 158 to the power of ring operator cos invisible function application 98 to the power of ring operator over denominator sin invisible function application 23 to the power of ring operator cos invisible function application 7 to the power of ring operator plus cos invisible function application 157 to the power of ring operator cos invisible function application 97 to the power of ring operator end fraction$ when simplified reduces to -

The expression $fraction numerator sin invisible function application 22 to the power of ring operator cos invisible function application 8 to the power of ring operator plus cos invisible function application 158 to the power of ring operator cos invisible function application 98 to the power of ring operator over denominator sin invisible function application 23 to the power of ring operator cos invisible function application 7 to the power of ring operator plus cos invisible function application 157 to the power of ring operator cos invisible function application 97 to the power of ring operator end fraction$ when simplified reduces to -

If A = $sin invisible function application fraction numerator 2 pi over denominator 7 end fraction plus sin invisible function application fraction numerator 4 pi over denominator 7 end fraction plus sin invisible function application fraction numerator 8 pi over denominator 7 end fraction$ and B = $cos invisible function application fraction numerator 2 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 4 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 8 pi over denominator 7 end fraction$ then $square root of A squared plus B squared end root$ is equal to

If A = $sin invisible function application fraction numerator 2 pi over denominator 7 end fraction plus sin invisible function application fraction numerator 4 pi over denominator 7 end fraction plus sin invisible function application fraction numerator 8 pi over denominator 7 end fraction$ and B = $cos invisible function application fraction numerator 2 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 4 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 8 pi over denominator 7 end fraction$ then $square root of A squared plus B squared end root$ is equal to

If $tan invisible function application B equals fraction numerator n sin invisible function application A cos invisible function application A over denominator 1 minus n cos squared invisible function application A end fraction$ then tan (A + B) equals

If $tan invisible function application B equals fraction numerator n sin invisible function application A cos invisible function application A over denominator 1 minus n cos squared invisible function application A end fraction$ then tan (A + B) equals

parallel

If x + y = 3 – cos4 $theta$ and x – y = 4 sin2 $theta$ then

If x + y = 3 – cos4 $theta$ and x – y = 4 sin2 $theta$ then

Which of the following is correct ?

Which of the following is correct ?

The value of the expression $open parentheses 1 plus cos invisible function application pi over 10 close parentheses open parentheses 1 plus cos invisible function application fraction numerator 3 pi over denominator 10 end fraction close parentheses open parentheses 1 plus cos invisible function application fraction numerator 7 pi over denominator 10 end fraction close parentheses open parentheses 1 plus cos invisible function application fraction numerator 9 pi over denominator 10 end fraction close parentheses$ is

The value of the expression $open parentheses 1 plus cos invisible function application pi over 10 close parentheses open parentheses 1 plus cos invisible function application fraction numerator 3 pi over denominator 10 end fraction close parentheses open parentheses 1 plus cos invisible function application fraction numerator 7 pi over denominator 10 end fraction close parentheses open parentheses 1 plus cos invisible function application fraction numerator 9 pi over denominator 10 end fraction close parentheses$ is

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.