Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

Sum of all divisors of 5400 whose unit digit is 0, is

5400
10800
16800
14400

The correct answer is: 16800

5400 = 2³ × 3³ × 5²
sum = (2 + 2² + 2³) (3⁰ + 3¹ + 3² + 3³) (5 + 5²)= 16800

Related Questions to study

If $cos invisible function application theta equals 1 half open parentheses a plus 1 over a close parentheses$ then $cos invisible function application 3 theta$ in terms of ‘a’ =

If $cos invisible function application theta equals 1 half open parentheses a plus 1 over a close parentheses$ then $cos invisible function application 3 theta$ in terms of ‘a’ =

Exact value of $cos invisible function application 20 to the power of ring operator plus 2 sin squared invisible function application 55 to the power of ring operator minus sin invisible function application 65 to the power of ring operator$ is -

Exact value of $cos invisible function application 20 to the power of ring operator plus 2 sin squared invisible function application 55 to the power of ring operator minus sin invisible function application 65 to the power of ring operator$ is -

If $fraction numerator sin invisible function application 2 alpha minus sin invisible function application 3 alpha plus sin invisible function application 4 alpha over denominator cos invisible function application 2 alpha minus cos invisible function application 3 alpha plus cos invisible function application 4 alpha end fraction equals tan invisible function application k alpha$ is an identity then the value of k is equal to -

If $fraction numerator sin invisible function application 2 alpha minus sin invisible function application 3 alpha plus sin invisible function application 4 alpha over denominator cos invisible function application 2 alpha minus cos invisible function application 3 alpha plus cos invisible function application 4 alpha end fraction equals tan invisible function application k alpha$ is an identity then the value of k is equal to -

parallel

If $tan invisible function application theta equals square root of a over b end root$ where a, b are positive reals then the value of $space sin invisible function application theta sec 7 theta plus cos invisible function application theta cosec to the power of blank 7 theta$ is -

If $tan invisible function application theta equals square root of a over b end root$ where a, b are positive reals then the value of $space sin invisible function application theta sec 7 theta plus cos invisible function application theta cosec to the power of blank 7 theta$ is -

The expression $fraction numerator sin invisible function application 22 to the power of ring operator cos invisible function application 8 to the power of ring operator plus cos invisible function application 158 to the power of ring operator cos invisible function application 98 to the power of ring operator over denominator sin invisible function application 23 to the power of ring operator cos invisible function application 7 to the power of ring operator plus cos invisible function application 157 to the power of ring operator cos invisible function application 97 to the power of ring operator end fraction$ when simplified reduces to -

The expression $fraction numerator sin invisible function application 22 to the power of ring operator cos invisible function application 8 to the power of ring operator plus cos invisible function application 158 to the power of ring operator cos invisible function application 98 to the power of ring operator over denominator sin invisible function application 23 to the power of ring operator cos invisible function application 7 to the power of ring operator plus cos invisible function application 157 to the power of ring operator cos invisible function application 97 to the power of ring operator end fraction$ when simplified reduces to -

If A = $sin invisible function application fraction numerator 2 pi over denominator 7 end fraction plus sin invisible function application fraction numerator 4 pi over denominator 7 end fraction plus sin invisible function application fraction numerator 8 pi over denominator 7 end fraction$ and B = $cos invisible function application fraction numerator 2 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 4 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 8 pi over denominator 7 end fraction$ then $square root of A squared plus B squared end root$ is equal to

If A = $sin invisible function application fraction numerator 2 pi over denominator 7 end fraction plus sin invisible function application fraction numerator 4 pi over denominator 7 end fraction plus sin invisible function application fraction numerator 8 pi over denominator 7 end fraction$ and B = $cos invisible function application fraction numerator 2 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 4 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 8 pi over denominator 7 end fraction$ then $square root of A squared plus B squared end root$ is equal to

parallel

If $tan invisible function application B equals fraction numerator n sin invisible function application A cos invisible function application A over denominator 1 minus n cos squared invisible function application A end fraction$ then tan (A + B) equals

If $tan invisible function application B equals fraction numerator n sin invisible function application A cos invisible function application A over denominator 1 minus n cos squared invisible function application A end fraction$ then tan (A + B) equals

If x + y = 3 – cos4 $theta$ and x – y = 4 sin2 $theta$ then

If x + y = 3 – cos4 $theta$ and x – y = 4 sin2 $theta$ then

Which of the following is correct ?

Which of the following is correct ?

parallel

The value of the expression $open parentheses 1 plus cos invisible function application pi over 10 close parentheses open parentheses 1 plus cos invisible function application fraction numerator 3 pi over denominator 10 end fraction close parentheses open parentheses 1 plus cos invisible function application fraction numerator 7 pi over denominator 10 end fraction close parentheses open parentheses 1 plus cos invisible function application fraction numerator 9 pi over denominator 10 end fraction close parentheses$ is

The value of the expression $open parentheses 1 plus cos invisible function application pi over 10 close parentheses open parentheses 1 plus cos invisible function application fraction numerator 3 pi over denominator 10 end fraction close parentheses open parentheses 1 plus cos invisible function application fraction numerator 7 pi over denominator 10 end fraction close parentheses open parentheses 1 plus cos invisible function application fraction numerator 9 pi over denominator 10 end fraction close parentheses$ is

If $A plus B equals fraction numerator pi over denominator 3 end fraction$ and cos A + cos B = 1, then -

If $A plus B equals fraction numerator pi over denominator 3 end fraction$ and cos A + cos B = 1, then -

Hydrogen atom does not emit X-rays because

Hydrogen atom does not emit X-rays because

Physics-General

parallel

The shortest wavelength of X-rays emitted from an X-rays tube depends upon

The shortest wavelength of X-rays emitted from an X-rays tube depends upon

Physics-General

According to Maxwell’s hypothesis, a changing electric field gives rise to

According to Maxwell’s hypothesis, a changing electric field gives rise to

Physics-General

The energy of X-ray photon is 2200 eV. Its frequency would be

The energy of X-ray photon is 2200 eV. Its frequency would be

Physics-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.