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Maths-

General

Easy

Question

If $f left parenthesis x right parenthesis equals l o g invisible function application open parentheses fraction numerator 1 plus x over denominator 1 minus x end fraction close parentheses$ then $f open parentheses x subscript 1 end subscript close parentheses plus f open parentheses x subscript 2 end subscript close parentheses equals$

$f (\frac{x_{1} + x_{2}}{1 + x_{1} x_{2}})$
$f (\frac{x_{1} + x_{2}}{1 - x_{1} x_{2}})$
$f (\frac{x_{1} - x_{2}}{1 + x_{1} x_{2}})$
$f (x_{1}) - f (x_{2})$

The correct answer is: $f open parentheses fraction numerator x subscript 1 end subscript plus x subscript 2 end subscript over denominator 1 plus x subscript 1 end subscript x subscript 2 end subscript end fraction close parentheses$

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