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Chemistry-

General

Easy

Question

The shortest and longest wave number in H spectrum of Lyman series is ( $R equals$ Rydberg constant)

$\frac{3}{4} R, R$
$\frac{1}{R}, \frac{4}{3} R$
$R, \frac{4}{3} R$
$R, \frac{3}{4} R$

The correct answer is: $fraction numerator 3 over denominator 4 end fraction R comma blank R$

Shortest $stack v with minus on top$ means shortest $E$ and vice versa
When, $n equals 1 comma blank n subscript 2 end subscript equals 2$
$stack v with minus on top equals R open parentheses fraction numerator 1 over denominator 1 to the power of 2 end exponent end fraction minus fraction numerator 1 over denominator 2 to the power of 2 end exponent end fraction close parentheses equals fraction numerator 3 over denominator 4 end fraction R$
Longest $stack v with minus on top$ means longest $E$
When $n subscript 1 end subscript equals 1 comma blank n subscript 2 end subscript equals infinity$
$stack v with minus on top equals R open parentheses fraction numerator 1 over denominator 1 to the power of 2 end exponent end fraction minus fraction numerator 1 over denominator infinity to the power of 2 end exponent end fraction close parentheses equals R$

Related Questions to study

The line spectrum of two elements is not identical because

The line spectrum of two elements is not identical because

Chemistry-General

How many electrons in an atom with atomic number 105 can have $open parentheses n plus l close parentheses equals 8 ?$

How many electrons in an atom with atomic number 105 can have $open parentheses n plus l close parentheses equals 8 ?$

Chemistry-General

$A r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals open vertical bar x close vertical bar blank a n d blank y equals 2 blank i s$

$A r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals open vertical bar x close vertical bar blank a n d blank y equals 2 blank i s$

parallel

$T h e blank a r e a blank b o u n d e d blank b y blank y to the power of 2 end exponent equals 4 a x blank a n d blank y equals m x blank i s fraction numerator a to the power of 2 end exponent over denominator 3 end fraction s q. blank u n i t s blank t h e n blank m equals blank$

$T h e blank a r e a blank b o u n d e d blank b y blank y to the power of 2 end exponent equals 4 a x blank a n d blank y equals m x blank i s fraction numerator a to the power of 2 end exponent over denominator 3 end fraction s q. blank u n i t s blank t h e n blank m equals blank$

$I f blank z to the power of 2 end exponent plus z plus 1 equals 0 comma$ where z is a complex number, then the value of $open parentheses z plus fraction numerator 1 over denominator z end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 2 end exponent plus fraction numerator 1 over denominator z to the power of 2 end exponent end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 1 end exponent plus fraction numerator 1 over denominator z to the power of 3 end exponent end fraction close parentheses to the power of 2 end exponent plus midline horizontal ellipsis plus open parentheses z to the power of 6 end exponent plus fraction numerator 1 over denominator z to the power of 6 end exponent end fraction close parentheses to the power of 2 end exponent text is end text$

$I f blank z to the power of 2 end exponent plus z plus 1 equals 0 comma$ where z is a complex number, then the value of $open parentheses z plus fraction numerator 1 over denominator z end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 2 end exponent plus fraction numerator 1 over denominator z to the power of 2 end exponent end fraction close parentheses to the power of 2 end exponent plus open parentheses z to the power of 1 end exponent plus fraction numerator 1 over denominator z to the power of 3 end exponent end fraction close parentheses to the power of 2 end exponent plus midline horizontal ellipsis plus open parentheses z to the power of 6 end exponent plus fraction numerator 1 over denominator z to the power of 6 end exponent end fraction close parentheses to the power of 2 end exponent text is end text$

$T h e blank a r e a blank o f blank t h e blank g r e a t e r blank r e g i o n blank b o u n d e d blank b y blank y equals C o s blank x semicolon blank y equals x plus 1 blank a n d blank y equals 0 blank i s$

$T h e blank a r e a blank o f blank t h e blank g r e a t e r blank r e g i o n blank b o u n d e d blank b y blank y equals C o s blank x semicolon blank y equals x plus 1 blank a n d blank y equals 0 blank i s$

parallel

$T h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank square root of x plus square root of y equals 1 blank i n blank t h e blank f i r s t blank q u a d r a n t blank i s$

$T h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank square root of x plus square root of y equals 1 blank i n blank t h e blank f i r s t blank q u a d r a n t blank i s$

The area of the region bounded by the curve y=f(x), x-axis and the ordinates x=a, x=b (a>b) is

For such questions, we should be careful about the limits on variable.

The area of the region bounded by the curve y=f(x), x-axis and the ordinates x=a, x=b (a>b) is

For such questions, we should be careful about the limits on variable.

$T h e blank l i n e blank x equals fraction numerator pi over denominator 4 end fraction blank d i v i d e s blank t h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals s i n blank x comma blank y equals c o s blank x blank a n d blank x minus a x i s open parentheses 0 less or equal than x less or equal than fraction numerator pi over denominator 2 end fraction close parentheses text into two regions of areas end text A subscript 1 end subscript blank a n d blank A subscript 2 end subscript blank t h e n blank A subscript 1 end subscript colon A subscript 2 end subscript equals$

$T h e blank l i n e blank x equals fraction numerator pi over denominator 4 end fraction blank d i v i d e s blank t h e blank a r e a blank o f blank t h e blank r e g i o n blank b o u n d e d blank b y blank y equals s i n blank x comma blank y equals c o s blank x blank a n d blank x minus a x i s open parentheses 0 less or equal than x less or equal than fraction numerator pi over denominator 2 end fraction close parentheses text into two regions of areas end text A subscript 1 end subscript blank a n d blank A subscript 2 end subscript blank t h e n blank A subscript 1 end subscript colon A subscript 2 end subscript equals$

parallel

$T h e blank a r e a blank e n c l o s e d blank b e t w e e n blank t h e blank c u r v e s blank y to the power of 2 end exponent equals x blank a n d blank y equals open vertical bar x close vertical bar blank i s$

$T h e blank a r e a blank e n c l o s e d blank b e t w e e n blank t h e blank c u r v e s blank y to the power of 2 end exponent equals x blank a n d blank y equals open vertical bar x close vertical bar blank i s$

The number of solutions of the equation
sin 2x = [1 + sin 2x] + [1 cos 2x] in $open square brackets 0 comma fraction numerator pi over denominator 2 end fraction close square brackets$ where [.] is the greatest
integer function is

The number of solutions of the equation
sin 2x = [1 + sin 2x] + [1 cos 2x] in $open square brackets 0 comma fraction numerator pi over denominator 2 end fraction close square brackets$ where [.] is the greatest
integer function is

If $c o s invisible function application x c o s invisible function application 2 x c o s invisible function application 4 x c o s invisible function application 8 x equals fraction numerator cosec invisible function application x over denominator 16 end fraction$ , then

If $c o s invisible function application x c o s invisible function application 2 x c o s invisible function application 4 x c o s invisible function application 8 x equals fraction numerator cosec invisible function application x over denominator 16 end fraction$ , then

parallel

$T h e blank a r e a blank o f blank t h e blank r e g i o n blank open parentheses i n blank s q. blank u n i t s close parentheses comma blank i n blank t h e blank f i r s t blank q u a d r a n t comma blank b o u n d e d blank b y blank t h e blank p a r a b o l a blank y equals 9 x to the power of 2 end exponent blank a n d blank t h e blank l i n e s blank x equals 0 comma y equals 1 blank a n d blank y equals 4 blank i s colon$

$T h e blank a r e a blank o f blank t h e blank r e g i o n blank open parentheses i n blank s q. blank u n i t s close parentheses comma blank i n blank t h e blank f i r s t blank q u a d r a n t comma blank b o u n d e d blank b y blank t h e blank p a r a b o l a blank y equals 9 x to the power of 2 end exponent blank a n d blank t h e blank l i n e s blank x equals 0 comma y equals 1 blank a n d blank y equals 4 blank i s colon$

Number of solutions of the equation Sin x + sin²x + sin³ x + sin⁴x + ……. Π= 2 where x Π[0,4Π], is

Number of solutions of the equation Sin x + sin²x + sin³ x + sin⁴x + ……. Π= 2 where x Π[0,4Π], is

The number of real solutions of the equation $s i n invisible function application open parentheses fraction numerator pi x over denominator 2 square root of 3 end fraction close parentheses equals x to the power of 2 end exponent minus 2 square root of 3 x plus 4$ is

The number of real solutions of the equation $s i n invisible function application open parentheses fraction numerator pi x over denominator 2 square root of 3 end fraction close parentheses equals x to the power of 2 end exponent minus 2 square root of 3 x plus 4$ is

parallel

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