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General
Easy

Question

If g(x) is a polynomial such that g(x) g(y) = g(x) + g(y) + g(xy) − 2 for all real x and y and g(2) = 5, then stack l i m with x rightwards arrow 2 below g ´ left parenthesis x right parenthesis is :

  1. 2    
  2. 3    
  3. 4    
  4. none of these    

The correct answer is: 4


    Since g(x) g(y) = g(x) + g(y) + g(xy) − 2 box enclose V x,…(1)
    for x = 2, y = 1, we have g(2) g(1) = g(2) + g(1) + g(2) − 2
    5 g(1) = 8 + g(1)
    4g(1) = 8Þg(1) = 2
    Putting y equals fraction numerator 1 over denominator x end fraction in (1), we get g left parenthesis x right parenthesis g open parentheses fraction numerator 1 over denominator x end fraction close parentheses equals g left parenthesis x right parenthesis plus g open parentheses fraction numerator 1 over denominator x end fraction close parentheses plus g left parenthesis 1 right parenthesis minus 2
    equals g left parenthesis x right parenthesis plus g open parentheses fraction numerator 1 over denominator x end fraction close parentheses plus 2 minus 2
    Þg left parenthesis x right parenthesis plus g open parentheses fraction numerator 1 over denominator x end fraction close parentheses minus g left parenthesis x right parenthesis. g open parentheses fraction numerator 1 over denominator x end fraction close parentheses equals 0Þg left parenthesis x right parenthesis open square brackets 1 minus g open parentheses fraction numerator 1 over denominator x end fraction close parentheses close square brackets minus 2 open square brackets 1 minus g open parentheses fraction numerator 1 over denominator x end fraction close parentheses close square brackets equals negative 1
    Þleft square bracket g left parenthesis x right parenthesis minus 1 right square bracket open square brackets g open parentheses fraction numerator 1 over denominator x end fraction close parentheses minus 1 close square brackets equals 1Þg(x) − 1 = xn
    g(x) = xn + 1
    Since g(2) = 5 = 22 + 1
    g(x) = x2 + 1
    g ´ left parenthesis x right parenthesis equals 2 x
    stack L t with x rightwards arrow 2 below g ´ left parenthesis x right parenthesis equals 2 left parenthesis 2 right parenthesis equals 4

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