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Maths-

General

Easy

Question

If the greatest value of the term independent of x in expansion of $open parentheses x s i n invisible function application p plus x to the power of negative 1 end exponent c o s invisible function application p close parentheses to the power of 10 end exponent$ is achieved at $P equals theta$ Then the locus of point from which pair of tangents be drawn to $x to the power of 2 end exponent plus y to the power of 2 end exponent equals 4$ including an angle $theta$ is

$x^{2} + y^{2} = 4 (4 + 2 \sqrt{2})$
$x^{2} + y^{2} = 4 (4 + \sqrt{2})$
$2 x^{2} + y^{2} = 4 (3 + 2 \sqrt{2})$
$x^{2} + y^{2} = 4 (1 + 2 \sqrt{2})$

The correct answer is: $x to the power of 2 end exponent plus y to the power of 2 end exponent equals 4 left parenthesis 4 plus 2 square root of 2 right parenthesis$

Related Questions to study

The sum of the series $fraction numerator 5 over denominator 1.4 to the power of 2 end exponent end fraction plus fraction numerator 11 over denominator 4 to the power of 2 end exponent times 7 to the power of 2 end exponent end fraction plus fraction numerator 17 over denominator 7 to the power of 2 end exponent times 10 to the power of 2 end exponent end fraction plus horizontal ellipsis.. plus$ is equal to

The sum of the series $fraction numerator 5 over denominator 1.4 to the power of 2 end exponent end fraction plus fraction numerator 11 over denominator 4 to the power of 2 end exponent times 7 to the power of 2 end exponent end fraction plus fraction numerator 17 over denominator 7 to the power of 2 end exponent times 10 to the power of 2 end exponent end fraction plus horizontal ellipsis.. plus$ is equal to

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Maths-General

Statement 1:The coefficient of $x to the power of n end exponent$ in the binomial expansion of $left parenthesis 1 minus x right parenthesis to the power of negative 2 end exponent$ is $left parenthesis n plus 1 right parenthesis$
Statement 2:The coefficient of $x to the power of r end exponent$ in $left parenthesis 1 minus x right parenthesis to the power of negative n end exponent$ when $n element of N$ is $blank to the power of n plus r minus 1 end exponent C subscript r end subscript$

Statement 1:The coefficient of $x to the power of n end exponent$ in the binomial expansion of $left parenthesis 1 minus x right parenthesis to the power of negative 2 end exponent$ is $left parenthesis n plus 1 right parenthesis$
Statement 2:The coefficient of $x to the power of r end exponent$ in $left parenthesis 1 minus x right parenthesis to the power of negative n end exponent$ when $n element of N$ is $blank to the power of n plus r minus 1 end exponent C subscript r end subscript$

parallel

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parallel

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The coefficient of $x to the power of 5 end exponent$ in the expansion of $open parentheses 1 plus x to the power of 2 end exponent close parentheses to the power of 5 end exponent open parentheses 1 plus x close parentheses to the power of 4 end exponent$ is

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parallel

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parallel

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