Maths-
General
Easy

Question

If the line x + y = k is a normal to the parabola y2 = 4x,then the value of k will be-

  1. 2    
  2. 1    
  3. 3    
  4. 4    

hintHint:

equation of normal of a parabola : y= mx -2am-am

The correct answer is: 3


    k= 3
    Given parabola: y2=4x
    Equation of normal of y2=4ax
    : y= mx -2am-am3. Here, a = 1
    Given normal : y= x- k
    On comparing, we get
    m =1 and -k= -2-1 = -3
    k=3

    the equation of tangent and normal in terms of the slope of the parabola are used to find the equations for any given slope.

    Related Questions to study

    General
    Maths-

    The equation of the normal to the parabola x2 = 8y whose slope is 1/m is

    equations of normal and tangent in terms of the slope are used to find the normal and tangent for any given slope.

    The equation of the normal to the parabola x2 = 8y whose slope is 1/m is

    Maths-General

    equations of normal and tangent in terms of the slope are used to find the normal and tangent for any given slope.

    General
    Maths-

    The equation of the normal to the parabola y2 + 12x = 0 at the upper end of it's latus rectum is

    the normal and tangent are always perpendicular to each other at any given point. Therefore, the product of slopes of tangent and normal is equal to -1.

    The equation of the normal to the parabola y2 + 12x = 0 at the upper end of it's latus rectum is

    Maths-General

    the normal and tangent are always perpendicular to each other at any given point. Therefore, the product of slopes of tangent and normal is equal to -1.

    General
    Maths-

    The equation of the normal having slope m of the parabola y2 = x + a is

    parametric form of slope of parabola = y+tx = 2at + at^3

    The equation of the normal having slope m of the parabola y2 = x + a is

    Maths-General

    parametric form of slope of parabola = y+tx = 2at + at^3

    parallel
    General
    Maths-

    Find the equation of normal to the curve 2y = 3–x2 at the point (1, 1)

    equation of straight line :
    (y-y1)=m(x-x1)

    Find the equation of normal to the curve 2y = 3–x2 at the point (1, 1)

    Maths-General

    equation of straight line :
    (y-y1)=m(x-x1)

    General
    Maths-

    The equations of the normal at the ends of the latus rectum of the parabola y2 = 4ax are given by-

    the slope of normal = -1/ slope of tangent.
    Equation of both normals can be generalized by multiplying both the equations.

    The equations of the normal at the ends of the latus rectum of the parabola y2 = 4ax are given by-

    Maths-General

    the slope of normal = -1/ slope of tangent.
    Equation of both normals can be generalized by multiplying both the equations.

    General
    Maths-

    The line ellx + my + n = 0 is a normal to the parabola y2 = 4 ax if-

    equation of normal of a parabola is given by:
    y = -tx + 2at + at3

    The line ellx + my + n = 0 is a normal to the parabola y2 = 4 ax if-

    Maths-General

    equation of normal of a parabola is given by:
    y = -tx + 2at + at3

    parallel
    General
    Maths-

    The equation of the normal to the parabola y2 = 16 x with slope – 1/4 is-


    equation of normal of a parabola is given by:
    y = -tx + 2at + at3
    equation of  normal in slope form: y = mx – 2am – am3

    The equation of the normal to the parabola y2 = 16 x with slope – 1/4 is-

    Maths-General


    equation of normal of a parabola is given by:
    y = -tx + 2at + at3
    equation of  normal in slope form: y = mx – 2am – am3

    General
    Maths-

    The equation of normal on point (2,4) to the parabola y2 = 8x is-

    we can also use equation of normal in slope form: y = mx – 2am – am3

    The equation of normal on point (2,4) to the parabola y2 = 8x is-

    Maths-General

    we can also use equation of normal in slope form: y = mx – 2am – am3

    General
    Maths-

    Area of triangle formed by the tangents at three points t1, t2 and t3 of the parabola y2 = 4ax is-

    area under a triangle is given by the determinant of the vertex points of the triangle.

    Area of triangle formed by the tangents at three points t1, t2 and t3 of the parabola y2 = 4ax is-

    Maths-General

    area under a triangle is given by the determinant of the vertex points of the triangle.

    parallel
    General
    Maths-

    The equation of the common tangents to the parabolas y2 = 4x and x2 = 32y is-

    the equation of tangent to the parabola y2= 4ax  is y = mx + a/m

    The equation of the common tangents to the parabolas y2 = 4x and x2 = 32y is-

    Maths-General

    the equation of tangent to the parabola y2= 4ax  is y = mx + a/m

    General
    Maths-

    The equation of tangent to the parabola x2 = y at one extremity of latus rectum in the first quadrant is

    equation of tangent : T=0 of
    X2= 4ay is given by 
    xx1=(y+y1)/2

    The equation of tangent to the parabola x2 = y at one extremity of latus rectum in the first quadrant is

    Maths-General

    equation of tangent : T=0 of
    X2= 4ay is given by 
    xx1=(y+y1)/2

    General
    Maths-

    The point of contact of the line 2x – y + 2 = 0 with the parabola y2 = 16 x is-

    for a line to be a tangent of a parabola, the value of a/m should be equal to the value of c.

    The point of contact of the line 2x – y + 2 = 0 with the parabola y2 = 16 x is-

    Maths-General

    for a line to be a tangent of a parabola, the value of a/m should be equal to the value of c.

    parallel
    General
    Maths-

    The point on the curve y2 = x the tangent at which makes an angle of 45º with x-axis will be given by

    the point of contact of a tangent with the curve is given by (x,y) =(a/m2, 2a/m). this is obtained by solving the equation of tangent with the equation of curve.

    The point on the curve y2 = x the tangent at which makes an angle of 45º with x-axis will be given by

    Maths-General

    the point of contact of a tangent with the curve is given by (x,y) =(a/m2, 2a/m). this is obtained by solving the equation of tangent with the equation of curve.

    General
    Maths-

    The equation of the tangent to the parabola y = 2 + 4x –4x2 with slope –4 is

    equation of a straight line : y-y1=m(x-x1)
    m is given, calculate x1 and y1 by differentiating the equation of parabola and equating it with the slope.

    The equation of the tangent to the parabola y = 2 + 4x –4x2 with slope –4 is

    Maths-General

    equation of a straight line : y-y1=m(x-x1)
    m is given, calculate x1 and y1 by differentiating the equation of parabola and equating it with the slope.

    General
    Maths-

    The equation of the tangent at vertex to the parabola 4y2 + 6x = 8y + 7 is

    if the slope of a line is infinite, then it is parallel to the y axis and the equation becomes x=a, where x is the x intercept.
    Slope of the tangent : dy/dx 

    The equation of the tangent at vertex to the parabola 4y2 + 6x = 8y + 7 is

    Maths-General

    if the slope of a line is infinite, then it is parallel to the y axis and the equation becomes x=a, where x is the x intercept.
    Slope of the tangent : dy/dx 

    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.