Turito Academy

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If <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator x to the power of 2 end exponent plus x plus 1 over denominator x to the power of 2 end exponent plus 2 x plus 1 end fraction equals A plus fraction numerator B over denominator x plus 1 end fraction plus fraction numerator C over denominator left parenthesis x plus 1 right parenthesis to the power of 2 end exponent end fraction" width="265" height="43" style="vertical-align:-16px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mfrac»«mrow»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«mo»+«/mo»«mi»x«/mi»«mo»+«/mo»«mn»1«/mn»«/mrow»«mrow»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«mo»+«/mo»«mn»2«/mn»«mi»x«/mi»«mo»+«/mo»«mn»1«/mn»«/mrow»«/mfrac»«mo»=«/mo»«mi»A«/mi»«mo»+«/mo»«mfrac»«mrow»«mi»B«/mi»«/mrow»«mrow»«mi»x«/mi»«mo»+«/mo»«mn»1«/mn»«/mrow»«/mfrac»«mo»+«/mo»«mfrac»«mrow»«mi»C«/mi»«/mrow»«mrow»«mo»(«/mo»«mi»x«/mi»«mo»+«/mo»«mn»1«/mn»«msup»«mrow»«mo»)«/mo»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«/mrow»«/mfrac»«/math»'/> then A-B=

Solution for the question - if (x^(2)+x+1)/(x^(2)+2x+1)=a+(b)/(x+1)+(c)/((x+1)^(2)) then a-b= 4c+13c2

If (x^(2)+x+1)/(x^(2)+2x+1)=a+(b)/(x+1)+(c)/((x+1)^(2)) then a--Turito

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Solution for the question - (x+1)/((2x-1)(3x+1))=(a)/(2x-1)+(b)/(3x+1) , then 16 a+9b= 865

(x+1)/((2x-1)(3x+1))=(a)/(2x-1)+(b)/(3x+1) , then 16 a+9b= -Turito

If <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator x to the power of 2 end exponent minus 10 x plus 13 over denominator left parenthesis x minus 1 right parenthesis open parentheses x to the power of 2 end exponent minus 5 x plus 6 close parentheses end fraction equals fraction numerator A over denominator x minus 1 end fraction plus fraction numerator B over denominator x minus 2 end fraction plus fraction numerator K over denominator x minus 3 end fraction" width="339" height="44" style="vertical-align:-17px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mfrac»«mrow»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«mo»-«/mo»«mn»10«/mn»«mi»x«/mi»«mo»+«/mo»«mn»13«/mn»«/mrow»«mrow»«mo»(«/mo»«mi»x«/mi»«mo»-«/mo»«mn»1«/mn»«mo»)«/mo»«mfenced separators=¨|¨»«mrow»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«mo»-«/mo»«mn»5«/mn»«mi»x«/mi»«mo»+«/mo»«mn»6«/mn»«/mrow»«/mfenced»«/mrow»«/mfrac»«mo»=«/mo»«mfrac»«mrow»«mi»A«/mi»«/mrow»«mrow»«mi»x«/mi»«mo»-«/mo»«mn»1«/mn»«/mrow»«/mfrac»«mo»+«/mo»«mfrac»«mrow»«mi»B«/mi»«/mrow»«mrow»«mi»x«/mi»«mo»-«/mo»«mn»2«/mn»«/mrow»«/mfrac»«mo»+«/mo»«mfrac»«mrow»«mi»K«/mi»«/mrow»«mrow»«mi»x«/mi»«mo»-«/mo»«mn»3«/mn»«/mrow»«/mfrac»«/math»'/> then K=

Solution for the question - if (x^(2)-10 x+13)/((x-1)(x^(2)-5x+6))=(a)/(x-1)+(b)/(x-2)+(k)/(x-3) thenk= -4-3

If (x^(2)-10 x+13)/((x-1)(x^(2)-5x+6))=(a)/(x-1)+(b)/(x-2)+(k)/-Turito

Dividend = Divisor <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABEAAAAKCAYAAABSfLWiAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAJufgqOgAAAC1JREFUeNpjYMAE1VDMQKIcUYpJMgCbJrIMQDZoNyUGUMUQir1DccBSLYrpDwAMJw7rHduE6QAAAE50RVh0TWF0aE1MADxtYXRoIHhtbG5zPSJodHRwOi8vd3d3LnczLm9yZy8xOTk4L01hdGgvTWF0aE1MIj48bW8+JiN4RDc7PC9tbz48L21hdGg+HjBxXgAAAABJRU5ErkJggg==" class="Wirisformula" alt="cross times" width="17" height="10" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math»'/> Quotient + remainder f(x) = g(x) <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABEAAAAKCAYAAABSfLWiAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAJufgqOgAAAC1JREFUeNpjYMAE1VDMQKIcUYpJMgCbJrIMQDZoNyUGUMUQir1DccBSLYrpDwAMJw7rHduE6QAAAE50RVh0TWF0aE1MADxtYXRoIHhtbG5zPSJodHRwOi8vd3d3LnczLm9yZy8xOTk4L01hdGgvTWF0aE1MIj48bW8+JiN4RDc7PC9tbz48L21hdGg+HjBxXgAAAABJRU5ErkJggg==" class="Wirisformula" alt="cross times" width="17" height="10" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math»'/> q(x) + r(x) f(x) = (x+1)<img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABEAAAAKCAYAAABSfLWiAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAJufgqOgAAAC1JREFUeNpjYMAE1VDMQKIcUYpJMgCbJrIMQDZoNyUGUMUQir1DccBSLYrpDwAMJw7rHduE6QAAAE50RVh0TWF0aE1MADxtYXRoIHhtbG5zPSJodHRwOi8vd3d3LnczLm9yZy8xOTk4L01hdGgvTWF0aE1MIj48bW8+JiN4RDc7PC9tbz48L21hdGg+HjBxXgAAAABJRU5ErkJggg==" class="Wirisformula" alt="cross times" width="17" height="10" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math»'/>  q1(x) + 7 f(-1) = 7 f(x) = (x-1) <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABEAAAAKCAYAAABSfLWiAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAJufgqOgAAAC1JREFUeNpjYMAE1VDMQKIcUYpJMgCbJrIMQDZoNyUGUMUQir1DccBSLYrpDwAMJw7rHduE6QAAAE50RVh0TWF0aE1MADxtYXRoIHhtbG5zPSJodHRwOi8vd3d3LnczLm9yZy8xOTk4L01hdGgvTWF0aE1MIj48bW8+JiN4RDc7PC9tbz48L21hdGg+HjBxXgAAAABJRU5ErkJggg==" class="Wirisformula" alt="cross times" width="17" height="10" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«/math»'/> q2(x) + 3 f(1) = 3 f(x) is divided with <img src="data:image/png;base64,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" class="Wirisformula" alt="x squared space minus 1" width="50" height="17" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»x«/mi»«mn»2«/mn»«/msup»«mo»§#160;«/mo»«mo»-«/mo»«mn»1«/mn»«/math»'/> Let remainder be ax + b and quotient  be q3(x) <img 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class="Wirisformula" alt="f left parenthesis x right parenthesis space equals space left parenthesis x squared space minus space 1 squared right parenthesis space cross times space q 3 space left parenthesis x right parenthesis space plus space a x space plus space b
f left parenthesis x right parenthesis space equals space left parenthesis x space plus 1 right parenthesis left parenthesis x minus 1 right parenthesis space cross times q 3 left parenthesis x right parenthesis space plus space a x space plus space b
f left parenthesis negative 1 right parenthesis space equals space minus a space plus space b space equals space 7
f left parenthesis 1 right parenthesis space equals space a space plus space b space equals space 3
S o l v i n g space b o t h space t h e s e space e q u a t i o n s
b space equals space 5 space a n d space a space equals space minus 2
R e m a i n d e r space a x space plus space b space equals space minus 2 x space plus space 5" width="298" height="161" style="vertical-align:-81px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»f«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mo»(«/mo»«msup»«mi»x«/mi»«mn»2«/mn»«/msup»«mo»§#160;«/mo»«mo»-«/mo»«mo»§#160;«/mo»«msup»«mn»1«/mn»«mn»2«/mn»«/msup»«mo»)«/mo»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mi»q«/mi»«mn»3«/mn»«mo»§#160;«/mo»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«mo»§#160;«/mo»«mo»+«/mo»«mo»§#160;«/mo»«mi»a«/mi»«mi»x«/mi»«mo»§#160;«/mo»«mo»+«/mo»«mo»§#160;«/mo»«mi»b«/mi»«mspace linebreak=¨newline¨/»«mi»f«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mo»(«/mo»«mi»x«/mi»«mo»§#160;«/mo»«mo»+«/mo»«mn»1«/mn»«mo»)«/mo»«mo»(«/mo»«mi»x«/mi»«mo»-«/mo»«mn»1«/mn»«mo»)«/mo»«mo»§#160;«/mo»«mo»§#215;«/mo»«mi»q«/mi»«mn»3«/mn»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«mo»§#160;«/mo»«mo»+«/mo»«mo»§#160;«/mo»«mi»a«/mi»«mi»x«/mi»«mo»§#160;«/mo»«mo»+«/mo»«mo»§#160;«/mo»«mi»b«/mi»«mspace linebreak=¨newline¨/»«mi»f«/mi»«mo»(«/mo»«mo»-«/mo»«mn»1«/mn»«mo»)«/mo»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mo»-«/mo»«mi»a«/mi»«mo»§#160;«/mo»«mo»+«/mo»«mo»§#160;«/mo»«mi»b«/mi»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mn»7«/mn»«mspace linebreak=¨newline¨/»«mi»f«/mi»«mo»(«/mo»«mn»1«/mn»«mo»)«/mo»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mi»a«/mi»«mo»§#160;«/mo»«mo»+«/mo»«mo»§#160;«/mo»«mi»b«/mi»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mn»3«/mn»«mspace linebreak=¨newline¨/»«mi»S«/mi»«mi»o«/mi»«mi»l«/mi»«mi»v«/mi»«mi»i«/mi»«mi»n«/mi»«mi»g«/mi»«mo»§#160;«/mo»«mi»b«/mi»«mi»o«/mi»«mi»t«/mi»«mi»h«/mi»«mo»§#160;«/mo»«mi»t«/mi»«mi»h«/mi»«mi»e«/mi»«mi»s«/mi»«mi»e«/mi»«mo»§#160;«/mo»«mi»e«/mi»«mi»q«/mi»«mi»u«/mi»«mi»a«/mi»«mi»t«/mi»«mi»i«/mi»«mi»o«/mi»«mi»n«/mi»«mi»s«/mi»«mspace linebreak=¨newline¨/»«mi»b«/mi»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mn»5«/mn»«mo»§#160;«/mo»«mi»a«/mi»«mi»n«/mi»«mi»d«/mi»«mo»§#160;«/mo»«mi»a«/mi»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mo»-«/mo»«mn»2«/mn»«mspace linebreak=¨newline¨/»«mi»R«/mi»«mi»e«/mi»«mi»m«/mi»«mi»a«/mi»«mi»i«/mi»«mi»n«/mi»«mi»d«/mi»«mi»e«/mi»«mi»r«/mi»«mo»§#160;«/mo»«mi»a«/mi»«mi»x«/mi»«mo»§#160;«/mo»«mo»+«/mo»«mo»§#160;«/mo»«mi»b«/mi»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mo»-«/mo»«mn»2«/mn»«mi»x«/mi»«mo»§#160;«/mo»«mo»+«/mo»«mo»§#160;«/mo»«mn»5«/mn»«/math»'/>

If the remainders of the polynomial <img src="data:image/png;base64,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" class="Wirisformula" alt="f left parenthesis x right parenthesis" width="29" height="17" style="vertical-align:-3px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mi»f«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«/math»'/> when divided by <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAACYAAAANCAYAAADFVhxbAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAMyZLetQAAAJ5JREFUeNpjYBhYoAbEtUB8gWGQgcVAnAbE/2lt0X9a6EsG4g4s4s1QuQFzGAicA2JxJH4iEE8Z6BADAQ8g7oOyXYB472CIShjYDcT20JwiTISBhDDVHFYAxL+AWG+wJH4QsAbiNdDojBwsDlMC4k1AzAXEPEB8hoiopLnDRIF4G5pDfKAF4IA5jA2I1wGxNBa55dCcSssCmZzMMnAAAExeMnZLoJj8AAAAXXRFWHRNYXRoTUwAPG1hdGggeG1sbnM9Imh0dHA6Ly93d3cudzMub3JnLzE5OTgvTWF0aC9NYXRoTUwiPjxtaT54PC9taT48bW8+KzwvbW8+PG1uPjE8L21uPjwvbWF0aD4PWQOIAAAAAElFTkSuQmCC" class="Wirisformula" alt="x plus 1" width="38" height="13" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mi»x«/mi»«mo»+«/mo»«mn»1«/mn»«/math»'/> and <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAACYAAAANCAYAAADFVhxbAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAMyZLetQAAAJ1JREFUeNpjYBhYoAbEtUB8gWGQgcVAnAbE/xkGKcDrsGQg7sAi3gyVGzCHgcA5IBZH4icC8ZSBDjEQ8ADiPijbBYj3DoaohIHdQGwPzSnCRBhICFPNYQVA/AuI9QZL4gcBayBeA43OyMHiMCUg3gTEXEDMA8RniIhKmjtMFIi3oTnEB1oADpjD2IB4HRBLY5FbDs2ptHQQOZll4AAAcYUqfhczavUAAABddEVYdE1hdGhNTAA8bWF0aCB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMTk5OC9NYXRoL01hdGhNTCI+PG1pPng8L21pPjxtbz4tPC9tbz48bW4+MTwvbW4+PC9tYXRoPuKTcfIAAAAASUVORK5CYII=" class="Wirisformula" alt="x minus 1" width="38" height="13" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mi»x«/mi»«mo»-«/mo»«mn»1«/mn»«/math»'/> are 7,3 then the remainder of <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAB0AAAARCAYAAAAhUad0AAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAOJ5y/mQAAAURJREFUeNpjYCANZAFxB4l6OqD6CAImIBZHE9MD4uMM5IGjUP04gQcQv4PiK0DMgqTRgExLjYH4MC5JkAVPkQzXgtIGUEspAYehlmOAICBejkW8C4hzKLQ0D1d6qAficiziO4DYFot4Mg6DmqFyyMASiPeiK1wHxP+RcCSS3CcgZsPhg3NoiS4RiKdgUccGNQcD3ABiWSzifwgkvD4o2wWbb5DAL2zZ5BsOxX8IxNduILYH4gtALEyKpeZAvB+HYnzBCwIFUAPx5UWswQuKw/l4fGKNQw4kvgYaxJF4LMWakCYBcRoODbiyjBIQbwJiLiDmAeIzeII3B2oORur1wqEBW+EgCsTb0CzxAeLFpBQOoGKPA0/wHEeKMzaoI6WxqFsOTdEEi0GQq58TSKFULfAnQPMnMVVWBhlVWxe2tGIMLXPpBgDjq0NSjPRGgQAAAGd0RVh0TWF0aE1MADxtYXRoIHhtbG5zPSJodHRwOi8vd3d3LnczLm9yZy8xOTk4L01hdGgvTWF0aE1MIj48bWk+ZjwvbWk+PG1vPig8L21vPjxtaT54PC9taT48bW8+KTwvbW8+PC9tYXRoPnnd0zkAAAAASUVORK5CYII=" class="Wirisformula" alt="f left parenthesis x right parenthesis" width="29" height="17" style="vertical-align:-3px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mi»f«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«/math»'/> when devided by <img src="data:image/png;base64,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" class="Wirisformula" alt="x to the power of 2 end exponent minus 1" width="46" height="17" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«mo»-«/mo»«mn»1«/mn»«/math»'/> is

Solution for the question - if the remainders of the polynomial f(x) when divided by x+1 and x-1 are7,3 then the remainder of f(x) when devided by x^(2)-1 is 3x+7

If the remainders of the polynomial f(x) when divided by x+1 an-Turito

If <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator 1 over denominator left parenthesis a x plus b right parenthesis left parenthesis c x plus d right parenthesis end fraction equals fraction numerator A over denominator a x plus b end fraction plus fraction numerator B over denominator c x plus d end fraction" width="268" height="37" style="vertical-align:-14px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mfrac»«mrow»«mn»1«/mn»«/mrow»«mrow»«mo»(«/mo»«mi»a«/mi»«mi»x«/mi»«mo»+«/mo»«mi»b«/mi»«mo»)«/mo»«mo»(«/mo»«mi»c«/mi»«mi»x«/mi»«mo»+«/mo»«mi»d«/mi»«mo»)«/mo»«/mrow»«/mfrac»«mo»=«/mo»«mfrac»«mrow»«mi»A«/mi»«/mrow»«mrow»«mi»a«/mi»«mi»x«/mi»«mo»+«/mo»«mi»b«/mi»«/mrow»«/mfrac»«mo»+«/mo»«mfrac»«mrow»«mi»B«/mi»«/mrow»«mrow»«mi»c«/mi»«mi»x«/mi»«mo»+«/mo»«mi»d«/mi»«/mrow»«/mfrac»«/math»'/> then <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator 1 over denominator left parenthesis a x plus b right parenthesis to the power of 2 end exponent left parenthesis c x plus d right parenthesis end fraction equals" width="148" height="39" style="vertical-align:-16px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mfrac»«mrow»«mn»1«/mn»«/mrow»«mrow»«mo»(«/mo»«mi»a«/mi»«mi»x«/mi»«mo»+«/mo»«mi»b«/mi»«msup»«mrow»«mo»)«/mo»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«mo»(«/mo»«mi»c«/mi»«mi»x«/mi»«mo»+«/mo»«mi»d«/mi»«mo»)«/mo»«/mrow»«/mfrac»«mo»=«/mo»«/math»'/>

Solution for the question - if (1)/((ax+b)(cx+d))=(a)/(ax+b)+(b)/(cx+d) then (1)/((ax+b)^(2)(cx+d))= (a)/((ax-b)^(2))+(ab)/(ax+b)+(b^(2))/(cx-d) '/>  (a)/((ax+b)^(2))+(ab)/(ax-b)+(b^(2))/(cx+d) '/>

If (1)/((ax+b)(cx+d))=(a)/(ax+b)+(b)/(cx+d) then (1)/((ax+b)^(2-Turito

The partial fractions of <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator left parenthesis x plus 1 right parenthesis to the power of 2 end exponent over denominator x open parentheses x to the power of 2 end exponent plus 1 close parentheses end fraction" width="75" height="43" style="vertical-align:-17px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mfrac»«mrow»«mo»(«/mo»«mi»x«/mi»«mo»+«/mo»«mn»1«/mn»«msup»«mrow»«mo»)«/mo»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«/mrow»«mrow»«mi»x«/mi»«mfenced separators=¨|¨»«mrow»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«mo»+«/mo»«mn»1«/mn»«/mrow»«/mfenced»«/mrow»«/mfrac»«/math»'/> are

Solution for the question - the partial fractions of ((x+1)^(2))/(x(x^(2)+1)) are (1)/(x)+(2)/(x^(2)+1)   (1)/(x)+(1)/(x^(2)+1)  (1)/(x)-(2)/(x^(2)+1)

The partial fractions of ((x+1)^(2))/(x(x^(2)+1)) are -Turito

The partial fractions of <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator 1 over denominator x to the power of 3 end exponent left parenthesis x plus 2 right parenthesis end fraction" width="75" height="40" style="vertical-align:-17px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mfrac»«mrow»«mn»1«/mn»«/mrow»«mrow»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»3«/mn»«/mrow»«/msup»«mo»(«/mo»«mi»x«/mi»«mo»+«/mo»«mn»2«/mn»«mo»)«/mo»«/mrow»«/mfrac»«/math»'/> are

Solution for the question - the partial fractions of (1)/(x^(3)(x+2)) are (1)/(8x)+(1)/(4x^(2))+(1)/(2x^(3))+(1)/(8(x+2)) '/>  (1)/(8x)-(1)/(4x^(2))-(1)/(2x^(3))+(1)/(8(x+2)) '/>

The partial fractions of (1)/(x^(3)(x+2)) are -Turito

Solution for the question - (3x^(2)+x+1)/((x-1)^(4))=(a)/(x-1)+(b)/((x-1)^(2))+(c)/((x-1)^(3))+(d)/((x-1)^(4))then a+b-c+d= 101

(3x^(2)+x+1)/((x-1)^(4))=(a)/(x-1)+(b)/((x-1)^(2))+(c)/((x-1)^(-Turito

The partial fractions of <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator x to the power of 2 end exponent over denominator open parentheses x to the power of 2 end exponent plus a to the power of 2 end exponent close parentheses open parentheses x to the power of 2 end exponent plus b to the power of 2 end exponent close parentheses end fraction" width="137" height="44" style="vertical-align:-17px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mfrac»«mrow»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«/mrow»«mrow»«mfenced separators=¨|¨»«mrow»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«mo»+«/mo»«msup»«mrow»«mi»a«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«/mrow»«/mfenced»«mfenced separators=¨|¨»«mrow»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«mo»+«/mo»«msup»«mrow»«mi»b«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«/mrow»«/mfenced»«/mrow»«/mfrac»«/math»'/> are

Solution for the question - the partial fractions of (x^(2))/((x^(2)+a^(2))(x^(2)+b^(2))) are (1)/(a^(2)-b^(2))[(1)/(x^(2)+a^(2))-(1)/(x^(2)+b^(2))] '/>

The partial fractions of (x^(2))/((x^(2)+a^(2))(x^(2)+b^(2))) a-Turito

The partial fractions of <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator 6 x to the power of 4 end exponent plus 5 x to the power of 3 end exponent plus x to the power of 2 end exponent plus 5 x plus 2 over denominator 1 plus 5 x plus 6 x to the power of 2 end exponent end fraction" width="184" height="42" style="vertical-align:-15px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mfrac»«mrow»«mn»6«/mn»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»4«/mn»«/mrow»«/msup»«mo»+«/mo»«mn»5«/mn»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»3«/mn»«/mrow»«/msup»«mo»+«/mo»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«mo»+«/mo»«mn»5«/mn»«mi»x«/mi»«mo»+«/mo»«mn»2«/mn»«/mrow»«mrow»«mn»1«/mn»«mo»+«/mo»«mn»5«/mn»«mi»x«/mi»«mo»+«/mo»«mn»6«/mn»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«/mrow»«/mfrac»«/math»'/> are

Solution for the question - the partial fractions of (6x^(4)+5x^(3)+x^(2)+5x+2)/(1+5x+6x^(2)) are -x^(2)+(1)/(1+2x)+(1)/(1+3x) '/>   x^(2)+(1)/(1+2x)-(1)/(1+3x) '/>

The partial fractions of (6x^(4)+5x^(3)+x^(2)+5x+2)/(1+5x+6x^(2-Turito

If <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAYUAAAApCAYAAADaijVpAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAbSkFbcgAABqFJREFUeNrtnX9kXlcYx4+IiIkSUxNRpaaqZsLMVM2M/FFVFWMmZiZCzMTUhJqpmRhRUzP7pyZqpkpM/6iaMVUTkX+mJn/MlJj9UTMlpiri9ZKdr/tE7q7749wfve9zz/l+eEhu3rzv+d57n/uc85xzntcY0hTvWtvnaSCEEPKStQ0GBUIIIePWNq1NMigQQgj5wdoZ+ZlBgRBCAuaytfdivzMokEFwKVDde9b61v6ytm3tjrWJQLSfsHbV2m/WduUcLJsoc0EGyH6GEdIW71jrWRsOTPeL8kCMg4fijQC0L1m7a+11a0Ny7Jh0Dm7QJfQFCULaAr3CLWs/W5sJTDv03kwceyvlmG8gO/Etb/32mbe2knJ8Wf7GoEA0cN3arLX3rX0TmPbP5AEZ5ztr5zzWfNJEabJh3vqD4YG1F2K/zzk4HoMCaYszkkIwcp9uB6Z/TUYLSJ9MWVs1/s+tfGnCnT9SAXoc1+TnaWv3eEqIEtBT/NVEeeR4J+ZUQOfgoTmcw3vq+QjhgN9NNJdCBghytW+YaELreZ4OogSkTpYSx76w9mEg+ockEIAR6bRhr9BJzzXv8dYfPBiqYWXHyzwVRAmnZFSQBJ2XO4Gcg9dSRu4oM3PVY80Ifk94+w+WsybamIYU0ixPB1HCusleCh3K0lT442riGPYL+b4qB6Oj5+gCg+GE9LpwAcZMlL9l+qhbIJWyUvJ/VozuFMyCta9y/n7L2vkAru3XJlr4EWc1gM4bNC7RtdvnqLUfE0HggrXveWo6A9J9mxX/d8PoTBdip+6WdFKymC8IGr5w2xxOLMNf3zbRvN+I57qPW9ux9ok53Lk8Ks8nBIxpun7zjMgNN5nRCzvHU6QCTLjFV55geeKbiQf7VMX3fsVEKRptrInz54H79mEA138ndv33xDcnA7n3sfoI+zGeiP5/TZTmPs/HAgmVZHmDg9Unf1o7LcFgo+ZnrEtwIIQQopy08gYAqRPkW7ECZbHmZ3xk3OcjQt6wGPpmTW5WJUQBaWv0jTzEEQx+MlGhsLSg4Vq6BLuF7/HBQO3UT0g7jlRkeSC3fjFxDJONyKVjcQByrVkTjq6lS8qsCWdQoH5CyADBwz9eMx+5f8whHEw093P+t0zpkh4fDNQeuv59Gq1BexYMyUMf778jwWA5EST6Be/hWrqk9wxGOl2/diFoD1k/IZ1LH6G8wf2C989LHwGX0iVMH1E79RPSAbBjteibpTASOJvxN9fSJZxopnbqJ6QDoLzBQsFrspaklildsmjci6sxKFB/UFSpH9MmRbVqtLe/6xrarhWE3eZFOzfTNq+VLV1SZvMagwL1B0Od+jFtklWrpivt77qGNmsFYXJ51OF1m7E2lS1dorXMBSEqnH2qA+3McmIt7d810aqZLmuo0vaudmi0FsQj7fgiKTEE10xyuK+l/ajTs9VxDVXaroEPTPm0G+YRFuj+XlLGF0mGcyx2qL3JWjVa2o86Pbc6rqFK2wnRRhlfJCk0UT+mCTDU+9zaPyZaW44NR8dTXpdcQqil/ajT86lo+NtEZX6xzn6iQxrAmASpR3IdkKMfz2k7cUOrP/movYwv+qjfxY9zaaJ+TBPcNdEyxHG5odck4idJbjbS0n60d9va5ZiGaxk9Fq0axuTz8MXwR6RNKEh3IaftxB2N/uSj9jK+6KN+Fz/Opan6MXWYlQsZB18ukbUksaes/QB1ek4njh3JeYBq1LAiD5IieoZUQas/+aS9ii/6pt/VjysFBeBaPwZULWtwX9IScX7JGe72lLUfPZHdlOOjDQSFNjU8dhxiMihUR6M/+aS9ii/6pt/Vjyulj4BL/Zi6JJeP4eenGa8tk3ppq/1ZdXqy8u8aNbxq3JabMn1UD23+5Jv2sr7om35XPy6MXnXrx9TlccrnPsh4bfLiamh/Vp2ej61d6YgGpBZuO7yOE83V0ehPvmkv64u+6Xf141yaqB9Tl0fm/7tXr8gJTCNZq0ZD+5G/m0vpUWOt9ERHNGDvwR8OrytTK4jo9yfftJf1Rd/0u/pxLk3Uj6kLlmZdl2Eu8p435fPTcNn41Xb7EZkxuTUtv0/KsbkOaQDIdWLFwrCJJuYupYxg+EX35dHsT75pL+uLvul39eNC6tSPaQqsK16TXg16OVhfPZMSBdcVth9tvSg3Y18uykxOJF9Xeg2OmWhCsi89q3nHtpNsNPuTj9rL+KKv177Ij53QWIztaMoxFsTT2XbSjdEKIaWoUj+mTYpq1Whvf9c1sFYQIZ7xH5lEgMJVxtbmAAACLnRFWHRNYXRoTUwAPG1hdGggeG1sbnM9Imh0dHA6Ly93d3cudzMub3JnLzE5OTgvTWF0aC9NYXRoTUwiPjxtZnJhYz48bXN1cD48bWk+eDwvbWk+PG1uPjQ8L21uPjwvbXN1cD48bXJvdz48bW8+KDwvbW8+PG1pPng8L21pPjxtbz4tPC9tbz48bWk+YTwvbWk+PG1vPik8L21vPjxtbz4oPC9tbz48bWk+eDwvbWk+PG1vPi08L21vPjxtaT5iPC9taT48bW8+KTwvbW8+PG1vPig8L21vPjxtaT54PC9taT48bW8+LTwvbW8+PG1pPmM8L21pPjxtbz4pPC9tbz48L21yb3c+PC9tZnJhYz48bW8+PTwvbW8+PG1pPlA8L21pPjxtbz4oPC9tbz48bWk+eDwvbWk+PG1vPik8L21vPjxtbz4rPC9tbz48bWZyYWM+PG1pPkE8L21pPjxtcm93PjxtaT54PC9taT48bW8+LTwvbW8+PG1pPmE8L21pPjwvbXJvdz48L21mcmFjPjxtbz4rPC9tbz48bWZyYWM+PG1pPkI8L21pPjxtcm93PjxtaT54PC9taT48bW8+LTwvbW8+PG1pPmI8L21pPjwvbXJvdz48L21mcmFjPjxtbz4rPC9tbz48bWZyYWM+PG1pPkM8L21pPjxtcm93PjxtaT54PC9taT48bW8+LTwvbW8+PG1pPmM8L21pPjwvbXJvdz48L21mcmFjPjwvbWF0aD4Y903lAAAAAElFTkSuQmCC" class="Wirisformula" alt="fraction numerator x to the power of 4 end exponent over denominator left parenthesis x minus a right parenthesis left parenthesis x minus b right parenthesis left parenthesis x minus c right parenthesis end fraction equals P left parenthesis x right parenthesis plus fraction numerator A over denominator x minus a end fraction plus fraction numerator B over denominator x minus b end fraction plus fraction numerator C over denominator x minus c end fraction" width="389" height="41" style="vertical-align:-14px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mfrac»«mrow»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»4«/mn»«/mrow»«/msup»«/mrow»«mrow»«mo»(«/mo»«mi»x«/mi»«mo»-«/mo»«mi»a«/mi»«mo»)«/mo»«mo»(«/mo»«mi»x«/mi»«mo»-«/mo»«mi»b«/mi»«mo»)«/mo»«mo»(«/mo»«mi»x«/mi»«mo»-«/mo»«mi»c«/mi»«mo»)«/mo»«/mrow»«/mfrac»«mo»=«/mo»«mi»P«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«mo»+«/mo»«mfrac»«mrow»«mi»A«/mi»«/mrow»«mrow»«mi»x«/mi»«mo»-«/mo»«mi»a«/mi»«/mrow»«/mfrac»«mo»+«/mo»«mfrac»«mrow»«mi»B«/mi»«/mrow»«mrow»«mi»x«/mi»«mo»-«/mo»«mi»b«/mi»«/mrow»«/mfrac»«mo»+«/mo»«mfrac»«mrow»«mi»C«/mi»«/mrow»«mrow»«mi»x«/mi»«mo»-«/mo»«mi»c«/mi»«/mrow»«/mfrac»«/math»'/> then <img src="data:image/png;base64,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" class="Wirisformula" alt="P left parenthesis x right parenthesis equals" width="48" height="16" style="vertical-align:-2px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mi»P«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«mo»=«/mo»«/math»'/>

Solution for the question - if (x^(4))/((x-a)(x-b)(x-c))=p(x)+(a)/(x-a)+(b)/(x-b)+(c)/(x-c) then p(x)= x+a+b+c '/>   x-a-b-c '/>   x-a-b '/>

If (x^(4))/((x-a)(x-b)(x-c))=p(x)+(a)/(x-a)+(b)/(x-b)+(c)/(x-c)-Turito

Let a,b,c such that <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator 1 over denominator left parenthesis 1 minus x right parenthesis left parenthesis 1 minus 2 x right parenthesis left parenthesis 1 minus 3 x right parenthesis end fraction equals fraction numerator a over denominator 1 minus x end fraction plus fraction numerator b over denominator 1 minus 2 x end fraction plus fraction numerator c over denominator 1 minus 3 x end fraction" width="381" height="37" style="vertical-align:-14px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mfrac»«mrow»«mn»1«/mn»«/mrow»«mrow»«mo»(«/mo»«mn»1«/mn»«mo»-«/mo»«mi»x«/mi»«mo»)«/mo»«mo»(«/mo»«mn»1«/mn»«mo»-«/mo»«mn»2«/mn»«mi»x«/mi»«mo»)«/mo»«mo»(«/mo»«mn»1«/mn»«mo»-«/mo»«mn»3«/mn»«mi»x«/mi»«mo»)«/mo»«/mrow»«/mfrac»«mo»=«/mo»«mfrac»«mrow»«mi»a«/mi»«/mrow»«mrow»«mn»1«/mn»«mo»-«/mo»«mi»x«/mi»«/mrow»«/mfrac»«mo»+«/mo»«mfrac»«mrow»«mi»b«/mi»«/mrow»«mrow»«mn»1«/mn»«mo»-«/mo»«mn»2«/mn»«mi»x«/mi»«/mrow»«/mfrac»«mo»+«/mo»«mfrac»«mrow»«mi»c«/mi»«/mrow»«mrow»«mn»1«/mn»«mo»-«/mo»«mn»3«/mn»«mi»x«/mi»«/mrow»«/mfrac»«/math»'/> then ,<img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator a over denominator 1 end fraction plus fraction numerator b over denominator 3 end fraction plus fraction numerator c over denominator 5 end fraction equals" width="106" height="35" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mfrac»«mrow»«mi»a«/mi»«/mrow»«mrow»«mn»1«/mn»«/mrow»«/mfrac»«mo»+«/mo»«mfrac»«mrow»«mi»b«/mi»«/mrow»«mrow»«mn»3«/mn»«/mrow»«/mfrac»«mo»+«/mo»«mfrac»«mrow»«mi»c«/mi»«/mrow»«mrow»«mn»5«/mn»«/mrow»«/mfrac»«mo»=«/mo»«/math»'/>?

Solution for the question - let a,b,c such that (1)/((1-x)(1-2x)(1-3x))=(a)/(1-x)+(b)/(1-2x)+(c)/(1-3x)then , (a)/(1)+(b)/(3)+(c)/(5)= ? (1)/(3) '/>   (1)/(5) '/>

Let a,b,c such that (1)/((1-x)(1-2x)(1-3x))=(a)/(1-x)+(b)/(1-2x-Turito

If <img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator 2 x plus 1 over denominator left parenthesis x minus 1 right parenthesis open parentheses x to the power of 2 end exponent plus 2 close parentheses end fraction equals fraction numerator A over denominator x minus 1 end fraction plus fraction numerator B x plus c over denominator x to the power of 2 end exponent plus 2 end fraction" width="246" height="40" style="vertical-align:-17px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mfrac»«mrow»«mn»2«/mn»«mi»x«/mi»«mo»+«/mo»«mn»1«/mn»«/mrow»«mrow»«mo»(«/mo»«mi»x«/mi»«mo»-«/mo»«mn»1«/mn»«mo»)«/mo»«mfenced separators=¨|¨»«mrow»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«mo»+«/mo»«mn»2«/mn»«/mrow»«/mfenced»«/mrow»«/mfrac»«mo»=«/mo»«mfrac»«mrow»«mi»A«/mi»«/mrow»«mrow»«mi»x«/mi»«mo»-«/mo»«mn»1«/mn»«/mrow»«/mfrac»«mo»+«/mo»«mfrac»«mrow»«mi»B«/mi»«mi»x«/mi»«mo»+«/mo»«mi»c«/mi»«/mrow»«mrow»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«mo»+«/mo»«mn»2«/mn»«/mrow»«/mfrac»«/math»'/> then B=

Solution for the question - if (2x+1)/((x-1)(x^(2)+2))=(a)/(x-1)+(bx+c)/(x^(2)+2) then b= -2-11

If (2x+1)/((x-1)(x^(2)+2))=(a)/(x-1)+(bx+c)/(x^(2)+2) then b= -Turito

If the remainders of the polynomial f(x) when divided by <img src="data:image/png;base64,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" class="Wirisformula" alt="x minus 1 comma x minus 2" width="81" height="15" style="vertical-align:-3px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mi»x«/mi»«mo»-«/mo»«mn»1«/mn»«mo»,«/mo»«mi»x«/mi»«mo»-«/mo»«mn»2«/mn»«/math»'/> are 2,5 then the remainder of <img src="data:image/png;base64,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" class="Wirisformula" alt="f left parenthesis x right parenthesis" width="29" height="17" style="vertical-align:-3px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mi»f«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«/math»'/> when divided by <img src="data:image/png;base64,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" class="Wirisformula" alt="left parenthesis x minus 1 right parenthesis left parenthesis x minus 2 right parenthesis" width="96" height="16" style="vertical-align:-2px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mo»(«/mo»«mi»x«/mi»«mo»-«/mo»«mn»1«/mn»«mo»)«/mo»«mo»(«/mo»«mi»x«/mi»«mo»-«/mo»«mn»2«/mn»«mo»)«/mo»«/math»'/> is

Solution for the question - if the remainders of the polynomial f(x) when divided by x-1,x-2 are 2,5then the remainder of f(x) when divided by (x-1)(x-2) is 3x-1

If the remainders of the polynomial f(x) when divided by x-1,x--Turito

Assertion : <img src="data:image/png;base64,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" class="Wirisformula" alt="f left parenthesis x right parenthesis equals s g n invisible function application left parenthesis x minus vertical line x vertical line right parenthesis" width="138" height="18" style="vertical-align:-4px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mi»f«/mi»«mo»(«/mo»«mi»x«/mi»«mo»)«/mo»«mo»=«/mo»«mi»s«/mi»«mi»g«/mi»«mi»n«/mi»«mo»⁡«/mo»«mo»(«/mo»«mi»x«/mi»«mo»-«/mo»«mo»|«/mo»«mi»x«/mi»«mo»|«/mo»«mo»)«/mo»«/math»'/> can never become positive. Reason : f(x) = sgn x is always a positive function.

Solution for the question - assertion : f(x)=sgn(x-|x|) can never become positive. reason : f(x) = sgnx is always a positive function. if (a) is false but (r) is true.

Assertion : f(x)=sgn(x-|x|) can never become positive. reason -Turito

<img src="data:image/png;base64,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" class="Wirisformula" alt="fraction numerator d x over denominator square root of 1 minus x to the power of 2 end exponent end root minus 1 end fraction" width="97" height="46" style="vertical-align:-23px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mfrac»«mrow»«mi»d«/mi»«mi»x«/mi»«/mrow»«mrow»«msqrt»«mn»1«/mn»«mo»-«/mo»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«/msqrt»«mo»-«/mo»«mn»1«/mn»«/mrow»«/mfrac»«/math»'/>=

Solution for the question - (dx)/(sqrt(1-x^(2))-1) = (1+sqrt(1-x^(2)))/(x)+2tan^(-1)sqrt((1-x)/(1+x))+c  (1+sqrt(1-x^(2)))/(x)+2tan^(-1)sqrt((1+x)/(1-x))+c

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4C
2
3C
4C+1

Take LCM on left hand side and simplify. Then equate the coefficients of RHS and LHS

The correct answer is: 2

Related Questions to study

If the remainders of the polynomial $f left parenthesis x right parenthesis$ when divided by $x plus 1$ and $x minus 1$ are 7,3 then the remainder of $f left parenthesis x right parenthesis$ when devided by $x to the power of 2 end exponent minus 1$ is

If the remainders of the polynomial $f left parenthesis x right parenthesis$ when divided by $x plus 1$ and $x minus 1$ are 7,3 then the remainder of $f left parenthesis x right parenthesis$ when devided by $x to the power of 2 end exponent minus 1$ is

The partial fractions of $fraction numerator left parenthesis x plus 1 right parenthesis to the power of 2 end exponent over denominator x open parentheses x to the power of 2 end exponent plus 1 close parentheses end fraction$ are

The partial fractions of $fraction numerator left parenthesis x plus 1 right parenthesis to the power of 2 end exponent over denominator x open parentheses x to the power of 2 end exponent plus 1 close parentheses end fraction$ are

The partial fractions of $fraction numerator 1 over denominator x to the power of 3 end exponent left parenthesis x plus 2 right parenthesis end fraction$ are

The partial fractions of $fraction numerator 1 over denominator x to the power of 3 end exponent left parenthesis x plus 2 right parenthesis end fraction$ are

The partial fractions of $fraction numerator 6 x to the power of 4 end exponent plus 5 x to the power of 3 end exponent plus x to the power of 2 end exponent plus 5 x plus 2 over denominator 1 plus 5 x plus 6 x to the power of 2 end exponent end fraction$ are

The partial fractions of $fraction numerator 6 x to the power of 4 end exponent plus 5 x to the power of 3 end exponent plus x to the power of 2 end exponent plus 5 x plus 2 over denominator 1 plus 5 x plus 6 x to the power of 2 end exponent end fraction$ are

If the remainders of the polynomial f(x) when divided by $x minus 1 comma x minus 2$ are 2,5 then the remainder of $f left parenthesis x right parenthesis$ when divided by $left parenthesis x minus 1 right parenthesis left parenthesis x minus 2 right parenthesis$ is

If the remainders of the polynomial f(x) when divided by $x minus 1 comma x minus 2$ are 2,5 then the remainder of $f left parenthesis x right parenthesis$ when divided by $left parenthesis x minus 1 right parenthesis left parenthesis x minus 2 right parenthesis$ is

Assertion : $f left parenthesis x right parenthesis equals s g n invisible function application left parenthesis x minus vertical line x vertical line right parenthesis$ can never become positive.
Reason : f(x) = sgn x is always a positive function.

Assertion : $f left parenthesis x right parenthesis equals s g n invisible function application left parenthesis x minus vertical line x vertical line right parenthesis$ can never become positive.
Reason : f(x) = sgn x is always a positive function.

$fraction numerator d x over denominator square root of 1 minus x to the power of 2 end exponent end root minus 1 end fraction$ =

$fraction numerator d x over denominator square root of 1 minus x to the power of 2 end exponent end root minus 1 end fraction$ =

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Can’t find what you’re looking for?

If then A-B=

4C 2 3C 4C+1

Take LCM on left hand side and simplify. Then equate the coefficients of RHS and LHS

The correct answer is: 2

Given : Taking LCM on left hand side and simplifying

Related Questions to study

, then

, then

If then K=

If then K=

If the remainders of the polynomial when divided by and are 7,3 then the remainder of when devided by is

If the remainders of the polynomial when divided by and are 7,3 then the remainder of when devided by is

If then

If then

The partial fractions of are

The partial fractions of are

The partial fractions of are

The partial fractions of are

then

then

The partial fractions of are

The partial fractions of are

The partial fractions of are

The partial fractions of are

If then

If then

Let a,b,c such that then ,?

Let a,b,c such that then ,?

If then B=

If then B=

If the remainders of the polynomial f(x) when divided by are 2,5 then the remainder of when divided by is

If the remainders of the polynomial f(x) when divided by are 2,5 then the remainder of when divided by is

Assertion : can never become positive.Reason : f(x) = sgn x is always a positive function.

Assertion : can never become positive.Reason : f(x) = sgn x is always a positive function.

=

=

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4C
2
3C
4C+1

If the remainders of the polynomial $f left parenthesis x right parenthesis$ when divided by $x plus 1$ and $x minus 1$ are 7,3 then the remainder of $f left parenthesis x right parenthesis$ when devided by $x to the power of 2 end exponent minus 1$ is

If the remainders of the polynomial $f left parenthesis x right parenthesis$ when divided by $x plus 1$ and $x minus 1$ are 7,3 then the remainder of $f left parenthesis x right parenthesis$ when devided by $x to the power of 2 end exponent minus 1$ is

The partial fractions of $fraction numerator left parenthesis x plus 1 right parenthesis to the power of 2 end exponent over denominator x open parentheses x to the power of 2 end exponent plus 1 close parentheses end fraction$ are

The partial fractions of $fraction numerator left parenthesis x plus 1 right parenthesis to the power of 2 end exponent over denominator x open parentheses x to the power of 2 end exponent plus 1 close parentheses end fraction$ are

The partial fractions of $fraction numerator 1 over denominator x to the power of 3 end exponent left parenthesis x plus 2 right parenthesis end fraction$ are

The partial fractions of $fraction numerator 1 over denominator x to the power of 3 end exponent left parenthesis x plus 2 right parenthesis end fraction$ are

The partial fractions of $fraction numerator 6 x to the power of 4 end exponent plus 5 x to the power of 3 end exponent plus x to the power of 2 end exponent plus 5 x plus 2 over denominator 1 plus 5 x plus 6 x to the power of 2 end exponent end fraction$ are

The partial fractions of $fraction numerator 6 x to the power of 4 end exponent plus 5 x to the power of 3 end exponent plus x to the power of 2 end exponent plus 5 x plus 2 over denominator 1 plus 5 x plus 6 x to the power of 2 end exponent end fraction$ are

If the remainders of the polynomial f(x) when divided by $x minus 1 comma x minus 2$ are 2,5 then the remainder of $f left parenthesis x right parenthesis$ when divided by $left parenthesis x minus 1 right parenthesis left parenthesis x minus 2 right parenthesis$ is

If the remainders of the polynomial f(x) when divided by $x minus 1 comma x minus 2$ are 2,5 then the remainder of $f left parenthesis x right parenthesis$ when divided by $left parenthesis x minus 1 right parenthesis left parenthesis x minus 2 right parenthesis$ is

Assertion : $f left parenthesis x right parenthesis equals s g n invisible function application left parenthesis x minus vertical line x vertical line right parenthesis$ can never become positive.
Reason : f(x) = sgn x is always a positive function.

Assertion : $f left parenthesis x right parenthesis equals s g n invisible function application left parenthesis x minus vertical line x vertical line right parenthesis$ can never become positive.
Reason : f(x) = sgn x is always a positive function.

$fraction numerator d x over denominator square root of 1 minus x to the power of 2 end exponent end root minus 1 end fraction$ =

$fraction numerator d x over denominator square root of 1 minus x to the power of 2 end exponent end root minus 1 end fraction$ =