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If x subscript i end subscript greater than 0 comma i equals 12 comma horizontal ellipsis comma 50 and x subscript 1 end subscript plus x subscript 2 end subscript plus midline horizontal ellipsis plus x subscript 50 end subscript equals 50, then the minimum value of fraction numerator 1 over denominator x subscript 1 end subscript end fraction plus fraction numerator 1 over denominator x subscript 2 end subscript end fraction plus midline horizontal ellipsis plus fraction numerator 1 over denominator x subscript 50 end subscript end fraction equals

  1. 50    
  2. left parenthesis 50 right parenthesis to the power of 2 end exponent    
  3. left parenthesis 50 right parenthesis to the power of 3 end exponent    
  4. left parenthesis 50 right parenthesis to the power of 4 end exponent    

The correct answer is: 50


    text We have  end text open parentheses x subscript 1 end subscript plus x subscript 2 end subscript plus x subscript 3 end subscript plus midline horizontal ellipsis plus x subscript 50 end subscript close parentheses open parentheses fraction numerator 1 over denominator x subscript 1 end subscript end fraction plus fraction numerator 1 over denominator x subscript 2 end subscript end fraction plus midline horizontal ellipsis fraction numerator 1 over denominator x subscript 50 end subscript end fraction close parentheses greater or equal than left parenthesis 50 right parenthesis to the power of 2 end exponent
    rightwards double arrow open parentheses fraction numerator 1 over denominator x subscript 1 end subscript end fraction plus fraction numerator 1 over denominator x subscript 2 end subscript end fraction plus midline horizontal ellipsis fraction numerator 1 over denominator x subscript 50 end subscript end fraction close parentheses greater or equal than left parenthesis 50 right parenthesis

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