Maths-
General
Easy

Question

log subscript y end subscript invisible function application x plus log subscript x end subscript invisible function application y equals 1 comma blank x to the power of 2 end exponent plus y equals 12 comma blankthen the value of x y is

  1. 9  
  2. 12  
  3. 15  
  4. 21  

The correct answer is: 9


    L e t blank t equals log subscript y end subscript invisible function application x open parentheses x comma blank y greater than 0 comma blank a n d blank not equal to 1 close parentheses comma blank t h e n blank t plus fraction numerator 1 over denominator t end fraction equals 2 blank o r blank open parentheses t minus 1 close parentheses to the power of 2 end exponent equals 0
    therefore t equals log subscript y end subscript invisible function application x equals 1 comma blank i. e. comma blank x equals y. blankWe getblank x to the power of 2 end exponent plus x minus 12 equals 0 x equals negative 4 comma blank 3
    x equals 3 onlyblank open parentheses negative 4 blank r e j e c t e d close parentheses

    Related Questions to study

    General
    Maths-

    e number of solutions of the equation tan invisible function application x plus sec invisible function application x minus 2 cos invisible function application x lying in the interval left square bracket 0 comma blank 2 pi right square bracket is

    e number of solutions of the equation tan invisible function application x plus sec invisible function application x minus 2 cos invisible function application x lying in the interval left square bracket 0 comma blank 2 pi right square bracket is

    Maths-General
    General
    Maths-

    a convex quadrilateral A B C D comma blank A B equals a comma blank B C equals b comma blank C D equals c blankand D A equals d. This quadrilateral is such that a circle can be inscribed in it and a circle can be also circumscribed about it, then tan to the power of 2 end exponent invisible function application open parentheses A divided by 2 close parentheses is equal to

    a convex quadrilateral A B C D comma blank A B equals a comma blank B C equals b comma blank C D equals c blankand D A equals d. This quadrilateral is such that a circle can be inscribed in it and a circle can be also circumscribed about it, then tan to the power of 2 end exponent invisible function application open parentheses A divided by 2 close parentheses is equal to

    Maths-General
    General
    Maths-

    triangle A B C comma line joining the circumcentre and orthocenter is parallel to side A C comma then the value of tan invisible function application A tan invisible function application C is equal to

    triangle A B C comma line joining the circumcentre and orthocenter is parallel to side A C comma then the value of tan invisible function application A tan invisible function application C is equal to

    Maths-General
    parallel
    General
    Maths-

    increment A B C comma blank a comma blank b comma blank A are given and c subscript 1 end subscript comma c subscript 2 end subscript are two values of the third side c. The sum of the areas of the two triangles with sides a comma blank b comma blank c subscript 1 end subscript andblank a comma blank b comma blank c subscript 2 end subscript is

    increment A B C comma blank a comma blank b comma blank A are given and c subscript 1 end subscript comma c subscript 2 end subscript are two values of the third side c. The sum of the areas of the two triangles with sides a comma blank b comma blank c subscript 1 end subscript andblank a comma blank b comma blank c subscript 2 end subscript is

    Maths-General
    General
    Maths-

    log subscript 2 end subscript invisible function application x plus log subscript 2 end subscript invisible function application y greater or equal than 6 comma then the least value of x plus y is

    log subscript 2 end subscript invisible function application x plus log subscript 2 end subscript invisible function application y greater or equal than 6 comma then the least value of x plus y is

    Maths-General
    General
    Maths-

    t a greater than 1 be a real number. Then the number of roots equation a to the power of 2 log subscript 2 end subscript invisible function application x end exponent equals 5 plus 4 x to the power of log subscript 2 end subscript invisible function application a end exponent has

    t a greater than 1 be a real number. Then the number of roots equation a to the power of 2 log subscript 2 end subscript invisible function application x end exponent equals 5 plus 4 x to the power of log subscript 2 end subscript invisible function application a end exponent has

    Maths-General
    parallel
    General
    Maths-

    of ordered pairs which satisfy the equation x to the power of 2 end exponent plus 2 x sin invisible function application open parentheses x y close parentheses plus 1 equals 0 areblank(where y element of open square brackets 0 comma blank 2 pi close square brackets right parenthesis

    of ordered pairs which satisfy the equation x to the power of 2 end exponent plus 2 x sin invisible function application open parentheses x y close parentheses plus 1 equals 0 areblank(where y element of open square brackets 0 comma blank 2 pi close square brackets right parenthesis

    Maths-General
    General
    Maths-

    increment A B C comma if sin to the power of 2 end exponent invisible function application fraction numerator A over denominator 2 end fraction comma sin to the power of 2 end exponent invisible function application fraction numerator B over denominator 2 end fraction and sin to the power of 2 end exponent invisible function application fraction numerator C over denominator 2 end fraction are in H.P., thenblank a comma blank b blankandblank c blankwill be in

    increment A B C comma if sin to the power of 2 end exponent invisible function application fraction numerator A over denominator 2 end fraction comma sin to the power of 2 end exponent invisible function application fraction numerator B over denominator 2 end fraction and sin to the power of 2 end exponent invisible function application fraction numerator C over denominator 2 end fraction are in H.P., thenblank a comma blank b blankandblank c blankwill be in

    Maths-General
    General
    Maths-

    Member of solutions of tan invisible function application open parentheses fraction numerator pi over denominator 2 end fraction sin invisible function application theta close parentheses equals cot invisible function application open parentheses fraction numerator pi over denominator 2 end fraction cos invisible function application theta close parentheses comma blank theta element of open square brackets 0 comma blank 6 pi close square brackets comma blankis

    Member of solutions of tan invisible function application open parentheses fraction numerator pi over denominator 2 end fraction sin invisible function application theta close parentheses equals cot invisible function application open parentheses fraction numerator pi over denominator 2 end fraction cos invisible function application theta close parentheses comma blank theta element of open square brackets 0 comma blank 6 pi close square brackets comma blankis

    Maths-General
    parallel
    General
    Maths-

    i s blank e q u a l blank t o

    i s blank e q u a l blank t o

    Maths-General
    General
    Maths-

    sin to the power of 2 end exponent invisible function application theta equals fraction numerator x to the power of 2 end exponent plus y to the power of 2 end exponent plus 1 over denominator 2 x end fraction comma blankthen x blankmust be

    sin to the power of 2 end exponent invisible function application theta equals fraction numerator x to the power of 2 end exponent plus y to the power of 2 end exponent plus 1 over denominator 2 x end fraction comma blankthen x blankmust be

    Maths-General
    General
    Maths-

    e equation cos to the power of 8 end exponent invisible function application x plus b cos to the power of 4 end exponent invisible function application x plus 1 equals 0 will have a solution if b belongs to

    e equation cos to the power of 8 end exponent invisible function application x plus b cos to the power of 4 end exponent invisible function application x plus 1 equals 0 will have a solution if b belongs to

    Maths-General
    parallel
    General
    Maths-

    e minimum vertical distance between the graphs of y equals 2 plus sin invisible function application x a n d blank y equals cos invisible function application x blank i s

    e minimum vertical distance between the graphs of y equals 2 plus sin invisible function application x a n d blank y equals cos invisible function application x blank i s

    Maths-General
    General
    Maths-

    e number of solutions of 2 sin to the power of 2 end exponent invisible function application x plus sin to the power of 2 end exponent invisible function application 2 x equals 2 comma blank x element of open square brackets 0 comma blank 2 pi close square brackets is

    e number of solutions of 2 sin to the power of 2 end exponent invisible function application x plus sin to the power of 2 end exponent invisible function application 2 x equals 2 comma blank x element of open square brackets 0 comma blank 2 pi close square brackets is

    Maths-General
    General
    Maths-

    e general solution of tan invisible function application theta plus tan invisible function application 2 theta plus tan invisible function application 3 theta equals 0 is

    e general solution of tan invisible function application theta plus tan invisible function application 2 theta plus tan invisible function application 3 theta equals 0 is

    Maths-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.