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    Maths-
    General
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    Question

    sin to the power of 2 end exponent invisible function application theta equals fraction numerator x to the power of 2 end exponent plus y to the power of 2 end exponent plus 1 over denominator 2 x end fraction comma blankthen x blankmust be

    1. negative 3  
    2. negative 2  
    3. 1  
    4. None of these  

    The correct answer is: 1

      sin to the power of 2 end exponent invisible function application theta less or equal than 1
      rightwards double arrow fraction numerator x to the power of 2 end exponent plus y to the power of 2 end exponent plus 1 over denominator 2 x end fraction less or equal than 1
      rightwards double arrow x to the power of 2 end exponent plus y to the power of 2 end exponent minus 2 x plus 1 less or equal than 0
      rightwards double arrow open parentheses x minus 1 close parentheses to the power of 2 end exponent plus y to the power of 2 end exponent less or equal than 0
      It is possible, iff x minus 1 blankand y equals 0

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