image

    Have a query? Ask a Tutor!!

    Access to best educators and exclusive paper discussions

    Offsite CampusTurito Championship

    Can’t find what you’re looking for?

    Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

    • Homework- One to One Solutions
    • Understand concepts to solve better
    • Get your doubts solved instantly
    Maths-
    General
    Easy

    Question

    e general solution of tan invisible function application theta plus tan invisible function application 2 theta plus tan invisible function application 3 theta equals 0 is

    1. theta equals n pi divided by 6 comma blank n element of Z  
    2. theta equals n pi plus-or-minus alpha comma blank n element of Z, where tan invisible function application alpha equals 1 divided by square root of 2  
    3. Both a and b  
    4. None of these  

    The correct answer is: theta equals n pi plus-or-minus alpha comma blank n element of Z, where tan invisible function application alpha equals 1 divided by square root of 2

      From the given equation, we have tan invisible function application theta plus tan invisible function application 2 theta plus tan invisible function application open parentheses theta plus 2 theta close parentheses equals 0
      rightwards double arrow open parentheses tan invisible function application theta plus tan invisible function application 2 theta close parentheses plus fraction numerator tan invisible function application theta plus tan invisible function application 2 theta over denominator 1 minus tan invisible function application theta tan invisible function application 2 theta end fraction equals 0
      rightwards double arrow open parentheses tan invisible function application theta plus tan invisible function application 2 theta close parentheses open square brackets 1 plus fraction numerator 1 over denominator 1 minus tan invisible function application theta tan invisible function application 2 theta end fraction close square brackets equals 0
      rightwards double arrow open parentheses tan invisible function application theta plus tan invisible function application 2 theta close parentheses open parentheses 2 minus tan invisible function application theta tan invisible function application 2 theta close parentheses equals 0
      rightwards double arrow tan invisible function application theta equals tan invisible function application open parentheses negative 2 theta close parentheses or 2 minus tan invisible function application theta open square brackets open parentheses 2 tan invisible function application theta close parentheses divided by open parentheses 1 minus tan to the power of 2 end exponent invisible function application theta close parentheses close square brackets equals 0
      rightwards double arrow theta equals n pi minus 2 theta blankor 1 minus 2 tan to the power of 2 end exponent invisible function application theta equals 0
      equals n pi divided by 3 or tan to the power of 2 end exponent invisible function application theta equals 1 divided by 2 equals tan to the power of 2 end exponent invisible function application alpha (say)
      Therefore, theta equals n pi plus-or-minus alpha comma where tan invisible function application alpha equals 1 divided by square root of 2

      Related Questions to study

      General
      Maths-

      sin invisible function application open parentheses alpha plus beta close parentheses equals 1 comma sin invisible function application open parentheses alpha minus beta close parentheses equals fraction numerator 1 over denominator 2 end fraction comma blankthentan invisible function application open parentheses alpha plus 2 beta close parentheses tan invisible function application open parentheses 2 alpha plus beta close parentheses is equal to, alpha comma blank beta element of open parentheses 0 comma blank pi divided by 2 close parentheses

      sin invisible function application open parentheses alpha plus beta close parentheses equals 1 comma sin invisible function application open parentheses alpha minus beta close parentheses equals fraction numerator 1 over denominator 2 end fraction comma blankthentan invisible function application open parentheses alpha plus 2 beta close parentheses tan invisible function application open parentheses 2 alpha plus beta close parentheses is equal to, alpha comma blank beta element of open parentheses 0 comma blank pi divided by 2 close parentheses

      Maths-General
      General
      Maths-

      alpha plus beta plus gamma equals 2 pi comma then

      alpha plus beta plus gamma equals 2 pi comma then

      Maths-General
      General
      Maths-

      i s blank e q u a l blank t o

      i s blank e q u a l blank t o

      Maths-General
      parallel
      General
      Maths-

      t area of triangle A B C isblank open parentheses square root of 3 minus 1 close parentheses divided by 2 comma blank b equals 2 andblank c equals open parentheses square root of 3 minus 1 close parentheses andblank angle A is acute. The measure of the angle C is

      t area of triangle A B C isblank open parentheses square root of 3 minus 1 close parentheses divided by 2 comma blank b equals 2 andblank c equals open parentheses square root of 3 minus 1 close parentheses andblank angle A is acute. The measure of the angle C is

      Maths-General
      General
      Maths-

      tan invisible function application beta equals 2 sin invisible function application alpha sin invisible function application gamma blank c o s e c blank open parentheses alpha plus gamma close parentheses comma blank t h e n cot invisible function application alpha comma cot invisible function application beta comma cot invisible function application gamma blankare in

      tan invisible function application beta equals 2 sin invisible function application alpha sin invisible function application gamma blank c o s e c blank open parentheses alpha plus gamma close parentheses comma blank t h e n cot invisible function application alpha comma cot invisible function application beta comma cot invisible function application gamma blankare in

      Maths-General
      General
      Maths-

      e equation sin to the power of 2 end exponent invisible function application theta equals fraction numerator x to the power of 2 end exponent plus y to the power of 2 end exponent over denominator 2 x y end fraction is possible if

      e equation sin to the power of 2 end exponent invisible function application theta equals fraction numerator x to the power of 2 end exponent plus y to the power of 2 end exponent over denominator 2 x y end fraction is possible if

      Maths-General
      parallel
      General
      Maths-

      increment A B C comma sin invisible function application A plus sin invisible function application B plus sin invisible function application C equals 1 plus square root of 2 and cos invisible function application A plus cos invisible function application plus cos invisible function application C equals square root of 2 if the triangle is

      increment A B C comma sin invisible function application A plus sin invisible function application B plus sin invisible function application C equals 1 plus square root of 2 and cos invisible function application A plus cos invisible function application plus cos invisible function application C equals square root of 2 if the triangle is

      Maths-General
      General
      Maths-

      ven A equals sin to the power of 2 end exponent invisible function application theta plus cos to the power of 2 end exponent invisible function application theta comma then for all real theta,

      ven A equals sin to the power of 2 end exponent invisible function application theta plus cos to the power of 2 end exponent invisible function application theta comma then for all real theta,

      Maths-General
      General
      Maths-

      open parentheses 1 plus tan invisible function application alpha close parentheses open parentheses 1 plus tan invisible function application 4 alpha close parentheses equals 2 comma blank alpha element of open parentheses 0 comma blank pi divided by 16 close parentheses then alpha is equal to

      open parentheses 1 plus tan invisible function application alpha close parentheses open parentheses 1 plus tan invisible function application 4 alpha close parentheses equals 2 comma blank alpha element of open parentheses 0 comma blank pi divided by 16 close parentheses then alpha is equal to

      Maths-General
      parallel
      General
      Maths-

      Let f open parentheses theta close parentheses equals sin invisible function application theta left parenthesis sin invisible function application theta plus sin invisible function application 3 theta right parenthesis. Then f left parenthesis theta right parenthesis is

      Let f open parentheses theta close parentheses equals sin invisible function application theta left parenthesis sin invisible function application theta plus sin invisible function application 3 theta right parenthesis. Then f left parenthesis theta right parenthesis is

      Maths-General
      General
      Maths-

      The value of tan invisible function application 9 degree minus tan invisible function application 27 degree minus tan invisible function application 63 degree plus tan invisible function application 81 degree blank i s

      The value of tan invisible function application 9 degree minus tan invisible function application 27 degree minus tan invisible function application 63 degree plus tan invisible function application 81 degree blank i s

      Maths-General
      General
      Maths-

      Ifblank sin invisible function application x plus cos invisible function application x equals fraction numerator square root of 7 over denominator 2 end fraction blankwhereblank x element of A comma then tan invisible function application fraction numerator x over denominator 2 end fraction blankis equal to

      Ifblank sin invisible function application x plus cos invisible function application x equals fraction numerator square root of 7 over denominator 2 end fraction blankwhereblank x element of A comma then tan invisible function application fraction numerator x over denominator 2 end fraction blankis equal to

      Maths-General
      parallel
      General
      Maths-

      If fraction numerator 3 pi over denominator 4 end fraction less than alpha less than pi comma blankthen square root of 2 cot invisible function application alpha plus fraction numerator 1 over denominator sin to the power of 2 end exponent invisible function application alpha end fraction end root blankis equal to

      If fraction numerator 3 pi over denominator 4 end fraction less than alpha less than pi comma blankthen square root of 2 cot invisible function application alpha plus fraction numerator 1 over denominator sin to the power of 2 end exponent invisible function application alpha end fraction end root blankis equal to

      Maths-General
      General
      Chemistry-

      Hydrogen burns in air with a

      Hydrogen burns in air with a

      Chemistry-General
      General
      Chemistry-

      Metal hydride on treatment with water gives

      Metal hydride on treatment with water gives

      Chemistry-General
      parallel

      card img

      With Turito Academy.

      card img

      With Turito Foundation.

      card img

      Get an Expert Advice From Turito.

      Turito Academy

      card img

      With Turito Academy.

      Test Prep

      card img

      With Turito Foundation.