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    Maths-
    General
    Easy

    Question

    of ordered pairs which satisfy the equation x to the power of 2 end exponent plus 2 x sin invisible function application open parentheses x y close parentheses plus 1 equals 0 areblank(where y element of open square brackets 0 comma blank 2 pi close square brackets right parenthesis

    1. 1  
    2. 2  
    3. 3  
    4. 0  

    The correct answer is: 2

      Given x to the power of 2 end exponent plus 2 x sin invisible function application open parentheses x comma y close parentheses plus 1 equals 0
      rightwards arrow open square brackets x plus sin invisible function application open parentheses x y close parentheses close square brackets to the power of 2 end exponent plus open square brackets 1 minus sin to the power of 2 end exponent invisible function application open parentheses x y close parentheses close square brackets equals 0
      rightwards arrow x plus sin invisible function application open parentheses x y close parentheses equals 0 and sin to the power of 2 end exponent invisible function application open parentheses x y close parentheses equals 1
      sin to the power of 2 end exponent invisible function application open parentheses x y close parentheses equals 1 blankgives sin invisible function application open parentheses x y close parentheses equals 1 or negative 1
      If sin invisible function application open parentheses x y close parentheses equals 1 rightwards double arrow x equals negative 1 blank rightwards double arrow sin invisible function application open parentheses negative y close parentheses equals 1 rightwards double arrow sin invisible function application y equals negative 1 comma thenblank
      The ordered pair is left parenthesis 1 comma blank 3 pi divided by 2 right parenthesis
      If sin invisible function application open parentheses x y close parentheses equals negative 1 blank rightwards double arrow x equals 1 blank rightwards double arrow sin invisible function application y equals negative 1 blank rightwards double arrow open parentheses negative 1 comma blank 3 pi divided by 2 close parentheses
      Thus, there are two ordered pairs

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