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Maths-

General

Easy

Question

The area bounded by the axes of reference and normal to $y equals I o g subscript e end subscript x$ at the point $left parenthesis 1 comma blank 0 right parenthesis$ is

1 $s q$ units
2 $s q$ units
$\frac{1}{2} s q$ units
None of these

The correct answer is: $fraction numerator 1 over denominator 2 end fraction s q$ units

See Fig 24.26.
$y equals I n x$
$fraction numerator d y over denominator d x end fraction equals fraction numerator 1 over denominator x end fraction$
At $x equals 1 comma$
slope of normal $equals negative 1$
$y equals negative 1 left parenthesis x minus 1 right parenthesis$
$y plus x equals 1$
Area $equals fraction numerator 1 over denominator 2 end fraction cross times 1 cross times 1 equals fraction numerator 1 over denominator 2 end fraction s q$ units

Figure 24.26
Hence, the correct answer is option (c).

Related Questions to study

The area bounded by the curve $y to the power of 2 end exponent equals 9 x$ and the line $x equals 1 comma x equals 4$ and $y equals 0$ in the first quadrant is

The area bounded by the curve $y to the power of 2 end exponent equals 9 x$ and the line $x equals 1 comma x equals 4$ and $y equals 0$ in the first quadrant is

The focus of the parabola $left parenthesis y minus 2 right parenthesis to the power of 2 end exponent equals 20 left parenthesis x plus 3 right parenthesis text is end text$

The focus of the parabola $left parenthesis y minus 2 right parenthesis to the power of 2 end exponent equals 20 left parenthesis x plus 3 right parenthesis text is end text$

The equation of the locus of a point which moves so as to be at equal distances from the point (a, 0) and the y-axis is

The equation of the locus of a point which moves so as to be at equal distances from the point (a, 0) and the y-axis is

parallel

$text The curve end text 16 x to the power of 2 end exponent plus 8 x y plus y to the power of 2 end exponent minus 74 x minus 78 y plus 212 equals 0 text represents end text$

$text The curve end text 16 x to the power of 2 end exponent plus 8 x y plus y to the power of 2 end exponent minus 74 x minus 78 y plus 212 equals 0 text represents end text$

The axis of the parabola $x to the power of 2 end exponent minus 4 x minus 3 y plus 10 equals 0 text is end text$

The axis of the parabola $x to the power of 2 end exponent minus 4 x minus 3 y plus 10 equals 0 text is end text$

Focus and directrix of the parabola $x to the power of 2 end exponent equals negative 8 a y text are end text$

Focus and directrix of the parabola $x to the power of 2 end exponent equals negative 8 a y text are end text$

parallel

If the vertex of a parabola be at origin and directrix be x + = 5 0, then its latus rectum is

If the vertex of a parabola be at origin and directrix be x + = 5 0, then its latus rectum is

10th-Grade-Math---USA

125, 80, 140, 135, 126, 140, 350, 75
Maximum value of given data _______________

125, 80, 140, 135, 126, 140, 350, 75
Maximum value of given data _______________

10th-Grade-Math---USAGeneral

$S subscript N end subscript 1$ reaction is favoured by:

$S subscript N end subscript 1$ reaction is favoured by:

Chemistry-General

parallel

Order of base strength of the compounds :
I)
II)
III) $N H subscript 2 end subscript superscript minus end superscript$
IV)

Order of base strength of the compounds :
I)
II)
III) $N H subscript 2 end subscript superscript minus end superscript$
IV)

Chemistry-General

The stability of the following carbocation decreases in the order:
I)
II)
III)
IV)

The stability of the following carbocation decreases in the order:
I)
II)
III)
IV)

Chemistry-General

Which of the following orders is correct for the ease of electrophile addition on these alkenes?
I)
II)
III)

Which of the following orders is correct for the ease of electrophile addition on these alkenes?
I)
II)
III)

Chemistry-General

parallel

$capital delta$ H for CaCO₃(s) $⟶$ CaO(s) + CO₂(g) is 176 kJ mol^–1 at 1240 K. The $capital delta$ E for the change is equal to

$capital delta$ H for CaCO₃(s) $⟶$ CaO(s) + CO₂(g) is 176 kJ mol^–1 at 1240 K. The $capital delta$ E for the change is equal to

Chemistry-General

The heat evolved in combustion if 112 litres of water gas (mixture of equal volume of H₂(g) and CO(g) is
H₂(g) + 1/2 O₂(g) = H₂O(g) $capital delta$ H = –241.8 kJ
CO(g) + 1/2 O₂(g) = CO₂(g) $capital delta$ H = –283 kJ

The heat evolved in combustion if 112 litres of water gas (mixture of equal volume of H₂(g) and CO(g) is
H₂(g) + 1/2 O₂(g) = H₂O(g) $capital delta$ H = –241.8 kJ
CO(g) + 1/2 O₂(g) = CO₂(g) $capital delta$ H = –283 kJ

Chemistry-General

(1) For the given heat of reaction,
i) C(s) + O₂(g) = CO₂(g) + 97 kcal
ii) CO₂(g) + C(s) = 2CO(g) – 39 kcal the heat of combustion of CO(g) is:

(1) For the given heat of reaction,
i) C(s) + O₂(g) = CO₂(g) + 97 kcal
ii) CO₂(g) + C(s) = 2CO(g) – 39 kcal the heat of combustion of CO(g) is:

Chemistry-General

parallel

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