Maths-
General
Easy

Question

The area of the circle and the area of a regular polygon of n sides, and of perimeter equal to that of the circle are in the ratio of

  1. tanopen parentheses fraction numerator pi over denominator 3 end fraction close parentheses: fraction numerator pi over denominator n end fraction  
  2. cot open parentheses fraction numerator pi over denominator n end fraction close parentheses:fraction numerator pi over denominator n end fraction  
  3. sinopen parentheses fraction numerator pi over denominator n end fraction close parentheses: fraction numerator pi over denominator n end fraction  
  4. cos open parentheses fraction numerator pi over denominator n end fraction close parentheses: fraction numerator pi over denominator n end fraction  

The correct answer is: tanopen parentheses fraction numerator pi over denominator 3 end fraction close parentheses: fraction numerator pi over denominator n end fraction


    The perimeter of a regular polygon of n sides = 2nr sin fraction numerator pi over denominator n end fraction
    If the radius of the circle is a then 2a = 2nr sin fraction numerator pi over denominator n end fraction ... (i)
    Now area of polygon = n open parentheses fraction numerator 1 over denominator 2 end fraction cross times 2 r sin invisible function application fraction numerator pi over denominator n end fraction r cos invisible function application fraction numerator pi over denominator n end fraction close parentheses
    ratio of areas of circle and polygon
    = fraction numerator pi a to the power of 2 end exponent over denominator n r sin invisible function application fraction numerator pi over denominator n end fraction cos invisible function application fraction numerator pi over denominator n end fraction end fraction= open parentheses tan invisible function application fraction numerator pi over denominator n end fraction close parentheses: fraction numerator pi over denominator n end fraction (from (i))

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