Maths-
General
Easy

Question

The ends of a line segment are P (1, 3) and Q (1, 1). R is a point on the line segment PQ such that PQ : QR = 1 : λ. If R is an interior point of the parabola y2 = 4x, then -

  1. lambdaelement of(0, 1)    
  2. lambda   
  3. lambdaelement ofopen parentheses 1 half comma 3 over 5 close parentheses    
  4. None of these    

hintHint:

assume R to be (x,y) and find x and y in terms of lambda.

The correct answer is: lambdaelement of(0, 1)



    λ ε (0,1)
    Let r = (x,y)
    x= λ+1/λ+1
    y= = 3λ+1/ λ+1
    r lies inside parabola => y2<4x

    (3λ+1/ λ+1)2 -4(λ+1/λ+1)<0
    5 λ2-2 λ-3<0
    This gives us λ ε (-3/5,1)
    Since λ>0,
    λ ε (0,1)

    if a point lies inside the curve, then it gives a negative value when we substitute its value in the curve
    zero when it lies on the curve and
    positive value when it lies outside the curve.

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