Maths-
General
Easy
Question
The function f(x) = | px − q|+ r|x|, ,where p > 0, q > 0, r > 0, assumes its minimum value only at one point if :
- p q
- r q
- r p
- p = q = r
The correct answer is: r p
f(x) = − px + q − rx, x ≤ 0
= − px + q + rx,0 < x <
= px + q + rx,
thus, f has two points of minimum if r = p.
In case p ¹ r, then x = 0 is pt. of minimum if r > p and is pt. of minimum if r < p.
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