Question
The incentre of the triangle formed by the links x=0, y=0 and 3x+4y=12 is at
- (1,1)
Hint:
A triangle in geometry is a particular kind of three-sided, two-dimensional polygon. The vertex of the triangle is where the two sides come together end to end. There is an angle created between two sides. Triangles have various characteristics, and each of these characteristics can be studied at various educational levels.
Here we have given the links x=0, y=0 and 3x+4y=12. We have to find the incentre of the triangle formed.
The correct answer is: (1,1)
Given That:
Here we have given the equation x=0, y=0 and 3x+4y=12.
Lets find x and y, we get:
Let x = 0, then y will be:
- 3(0)+4y=12
- y=12/4 = 3
Let y = 0, then y will be:
- 3(x)+4(0)=12
- x=12/3 = 4
A = x1,y1 = 0,0
B = x2,y2 = 0,3
C = x3,y3 = 4,0
Now,
Coordinates of incentre are:
>>> The Coordinate of incentre is (1,1).
In order to answer this question, we used the formula for the coordinates of a triangle's in-center when the lengths of its sides a, b, and c are known, as well as the coordinates of its vertices. The incentre is (1,1).
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