image

    Have a query? Ask a Tutor!!

    Access to best educators and exclusive paper discussions

    Offsite CampusTurito Championship

    Can’t find what you’re looking for?

    Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

    • Homework- One to One Solutions
    • Understand concepts to solve better
    • Get your doubts solved instantly
    Maths-
    General
    Easy

    Question

    The total number of solution of sin to the power of 4 end exponent invisible function application x plus cos to the power of 4 end exponent invisible function application x equals sin invisible function application x cos invisible function application x inblank open square brackets 0 comma blank 2 pi close square brackets blankis equal to

    1. 2  
    2. 4  
    3. 6  
    4. None of these  

    The correct answer is: 2

      sin to the power of 4 end exponent invisible function application x plus cos to the power of 4 end exponent invisible function application x equals sin invisible function application x cos invisible function application x
      rightwards double arrow open parentheses sin to the power of 2 end exponent invisible function application x plus cos to the power of 2 end exponent invisible function application x close parentheses to the power of 2 end exponent minus 2 sin to the power of 2 end exponent invisible function application x cos to the power of 2 end exponent invisible function application x equals sin invisible function application x cos invisible function application x
      rightwards double arrow 1 minus fraction numerator sin to the power of 2 end exponent invisible function application 2 x over denominator 2 end fraction equals fraction numerator sin invisible function application 2 x over denominator 2 end fraction
      rightwards double arrow sin to the power of 2 end exponent invisible function application 2 x plus sin invisible function application 2 x minus 2 equals 0
      rightwards double arrow open parentheses sin invisible function application 2 x plus 2 close parentheses open parentheses sin invisible function application 2 x minus 1 close parentheses equals 0
      rightwards double arrow sin invisible function application 2 x equals 1
      rightwards double arrow 2 x equals open parentheses 4 n plus 1 close parentheses fraction numerator pi over denominator 2 end fraction comma blank n element of Z
      rightwards double arrow x equals open parentheses 4 n plus 1 close parentheses fraction numerator pi over denominator 4 end fraction comma n element of Z
      equals fraction numerator pi over denominator 4 end fraction comma fraction numerator 5 pi over denominator 4 end fraction open parentheses because x element of open square brackets 0 comma blank 2 pi close square brackets close parentheses
      Thus, there are two solutions

      Related Questions to study

      General
      Maths-

      I f cos to the power of 2 end exponent invisible function application A plus cos to the power of 2 end exponent invisible function application B plus cos to the power of 2 end exponent invisible function application C equals 1 comma blank t h e n blank increment A B C blank i s

      I f cos to the power of 2 end exponent invisible function application A plus cos to the power of 2 end exponent invisible function application B plus cos to the power of 2 end exponent invisible function application C equals 1 comma blank t h e n blank increment A B C blank i s

      Maths-General
      General
      Maths-

      If cos invisible function application p theta plus cos invisible function application q theta equals 0 comma blankthen the different values of theta are in A.P. where the common difference is

      If cos invisible function application p theta plus cos invisible function application q theta equals 0 comma blankthen the different values of theta are in A.P. where the common difference is

      Maths-General
      General
      Maths-

      If x subscript 1 end subscript blank a n d blank x subscript 2 end subscript are the roots of the equation e to the power of 2 end exponent blank. x to the power of ln invisible function application x end exponent equals x to the power of 3 end exponent blank w i t h blank x subscript 1 end subscript greater than x subscript 2 end subscript comma then

      If x subscript 1 end subscript blank a n d blank x subscript 2 end subscript are the roots of the equation e to the power of 2 end exponent blank. x to the power of ln invisible function application x end exponent equals x to the power of 3 end exponent blank w i t h blank x subscript 1 end subscript greater than x subscript 2 end subscript comma then

      Maths-General
      parallel
      General
      Maths-

      sec to the power of 2 end exponent invisible function application theta equals fraction numerator 4 x y over denominator open parentheses x plus y close parentheses to the power of 2 end exponent end fraction is true if and only if

      sec to the power of 2 end exponent invisible function application theta equals fraction numerator 4 x y over denominator open parentheses x plus y close parentheses to the power of 2 end exponent end fraction is true if and only if

      Maths-General
      General
      Maths-

      Product of roots of the equation fraction numerator log subscript 8 end subscript invisible function application open parentheses 8 divided by x to the power of 2 end exponent close parentheses over denominator open parentheses log subscript 8 end subscript invisible function application x close parentheses to the power of 2 end exponent end fraction equals 3 is

      Product of roots of the equation fraction numerator log subscript 8 end subscript invisible function application open parentheses 8 divided by x to the power of 2 end exponent close parentheses over denominator open parentheses log subscript 8 end subscript invisible function application x close parentheses to the power of 2 end exponent end fraction equals 3 is

      Maths-General
      General
      Maths-

      The value of the expression fraction numerator 2 open parentheses sin invisible function application 1 degree plus sin invisible function application 2 degree plus sin invisible function application 3 degree plus horizontal ellipsis plus sin invisible function application 89 degree close parentheses over denominator 2 open parentheses cos invisible function application 1 degree plus cos invisible function application 2 degree plus horizontal ellipsis plus cos invisible function application 44 degree close parentheses plus 1 end fraction equals

      The value of the expression fraction numerator 2 open parentheses sin invisible function application 1 degree plus sin invisible function application 2 degree plus sin invisible function application 3 degree plus horizontal ellipsis plus sin invisible function application 89 degree close parentheses over denominator 2 open parentheses cos invisible function application 1 degree plus cos invisible function application 2 degree plus horizontal ellipsis plus cos invisible function application 44 degree close parentheses plus 1 end fraction equals

      Maths-General
      parallel
      General
      Maths-

      Inblank increment A B C comma ifblank A equals 30 degree comma blank b equals 2 comma blank c equals square root of 3 plus 1 comma blankthenfraction numerator C minus B over denominator 2 end fraction blankis equal to

      Inblank increment A B C comma ifblank A equals 30 degree comma blank b equals 2 comma blank c equals square root of 3 plus 1 comma blankthenfraction numerator C minus B over denominator 2 end fraction blankis equal to

      Maths-General
      General
      Maths-

      I f blank x comma blank y comma blank z blank a r e blank i n blank A. P comma blank t h e n fraction numerator sin invisible function application x minus sin invisible function application z over denominator cos invisible function application z minus cos invisible function application x end fraction blank i s blank e q u a l blank t o

      I f blank x comma blank y comma blank z blank a r e blank i n blank A. P comma blank t h e n fraction numerator sin invisible function application x minus sin invisible function application z over denominator cos invisible function application z minus cos invisible function application x end fraction blank i s blank e q u a l blank t o

      Maths-General
      General
      Maths-

      The general value of x satisfying the equation 2 cot to the power of 2 end exponent invisible function application x plus 2 square root of 3 cot invisible function application x plus 4 blank c o s e c blank x plus 8 equals 0 is

      The general value of x satisfying the equation 2 cot to the power of 2 end exponent invisible function application x plus 2 square root of 3 cot invisible function application x plus 4 blank c o s e c blank x plus 8 equals 0 is

      Maths-General
      parallel
      General
      Maths-

      If open parentheses 21.4 close parentheses to the power of a end exponent equals open parentheses 0.00214 close parentheses to the power of b end exponent equals 100 comma then the value of fraction numerator 1 over denominator b end fraction minus fraction numerator 1 over denominator b end fraction is

      If open parentheses 21.4 close parentheses to the power of a end exponent equals open parentheses 0.00214 close parentheses to the power of b end exponent equals 100 comma then the value of fraction numerator 1 over denominator b end fraction minus fraction numerator 1 over denominator b end fraction is

      Maths-General
      General
      Maths-

      In triangle A B C comma fraction numerator a over denominator b end fraction equals fraction numerator 2 over denominator 3 end fraction blankand sec to the power of 2 end exponent invisible function application A equals fraction numerator 8 over denominator 5 end fraction. Then the number of triangles satisfying these conditions is

      In triangle A B C comma fraction numerator a over denominator b end fraction equals fraction numerator 2 over denominator 3 end fraction blankand sec to the power of 2 end exponent invisible function application A equals fraction numerator 8 over denominator 5 end fraction. Then the number of triangles satisfying these conditions is

      Maths-General
      General
      Maths-

      The greatest value of sin to the power of 4 end exponent invisible function application theta plus cos to the power of 4 end exponent invisible function application theta is

      The greatest value of sin to the power of 4 end exponent invisible function application theta plus cos to the power of 4 end exponent invisible function application theta is

      Maths-General
      parallel
      General
      Maths-

      If in a increment A B C comma cos invisible function application 3 A plus cos invisible function application 3 B plus cos invisible function application 3 C equals 1 comma blankthen one angle must be exactly equal to

      If in a increment A B C comma cos invisible function application 3 A plus cos invisible function application 3 B plus cos invisible function application 3 C equals 1 comma blankthen one angle must be exactly equal to

      Maths-General
      General
      Maths-

      The solution of 4 sin to the power of 2 end exponent invisible function application x plus tan to the power of 2 end exponent invisible function application x plus c o s e c to the power of 2 end exponent x plus cot to the power of 2 end exponent invisible function application x minus 6 equals 0 is

      The solution of 4 sin to the power of 2 end exponent invisible function application x plus tan to the power of 2 end exponent invisible function application x plus c o s e c to the power of 2 end exponent x plus cot to the power of 2 end exponent invisible function application x minus 6 equals 0 is

      Maths-General
      General
      Maths-

      In triangle A B C comma blankifblank A minus B equals 120 degree blankandblank R equals 8 r where R blankandblank r have their usual meaning, then cos invisible function application C equals

      In triangle A B C comma blankifblank A minus B equals 120 degree blankandblank R equals 8 r where R blankandblank r have their usual meaning, then cos invisible function application C equals

      Maths-General
      parallel

      card img

      With Turito Academy.

      card img

      With Turito Foundation.

      card img

      Get an Expert Advice From Turito.

      Turito Academy

      card img

      With Turito Academy.

      Test Prep

      card img

      With Turito Foundation.