Physics
Fluid-Mechanics
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A body of density d is counterpoised by M g of weights of density d1 in air of density d. Then the true mass of the body is

  1. M
  2. M open parentheses 1 minus d over d subscript 2 close parentheses
  3. M open parentheses 1 minus d over d subscript 1 close parentheses
  4. fraction numerator M open parentheses 1 minus d divided by d subscript 2 close parentheses over denominator open parentheses 1 minus d divided by d subscript 1 close parentheses end fraction

The correct answer is: fraction numerator M open parentheses 1 minus d divided by d subscript 2 close parentheses over denominator open parentheses 1 minus d divided by d subscript 1 close parentheses end fraction


    Let M0 = mass of body in vacuum.
    Apparent weight of the body in air = Apparent weight of standard weights in air
    rightwards double arrowActual weight - upthrust due to displaced air
    = Actual weight - upthrust due to displaced air
    table attributes columnalign left columnspacing 1em rowspacing 4 pt end attributes row cell not stretchy rightwards double arrow M subscript 0 g minus open parentheses M subscript 0 over d subscript 1 close parentheses d g equals M g minus open parentheses M over d subscript 2 close parentheses d g end cell row cell not stretchy rightwards double arrow M subscript 0 equals fraction numerator M open square brackets 1 minus d over d subscript 2 close square brackets over denominator open square brackets 1 minus d over d subscript 1 close square brackets end fraction end cell end table

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