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Physics

Fluid-Mechanics

Easy

Question

$text In the case if end text P subscript 1 text and end text P subscript 2 text are pressures of the liquid at end text x equals L over 3 text and end text x equals L over 2 comma text the value of end text P subscript 2 minus P subscript 1 equals$

$\frac{5 ρ ω^{2} L^{2}}{9}$
$\frac{5 ρ ω^{2} L^{2}}{18}$
$\frac{5 ρ ω^{2} L^{2}}{36}$
$\frac{5 ρ ω^{2} L^{2}}{72}$

The correct answer is: $fraction numerator 5 rho omega squared L squared over denominator 72 end fraction$

$table attributes columnalign left columnspacing 1em rowspacing 4 pt end attributes row cell text At end text x equals L over 3 comma P subscript 1 equals P subscript 0 plus fraction numerator rho omega squared L squared over denominator 18 end fraction end cell row cell text At end text x equals L over 2 comma P subscript 2 equals P subscript 0 plus fraction numerator rho omega squared L squared over denominator 8 end fraction end cell row cell text Now end text P subscript 2 minus P subscript 1 equals rho omega squared L squared open parentheses 1 over 8 minus 1 over 18 close parentheses equals fraction numerator 5 rho omega squared L squared over denominator 72 end fraction end cell end table$

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