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text  In the case if  end text P subscript 1 text  and  end text P subscript 2 text  are pressures of the liquid at  end text x equals L over 3 text  and  end text x equals L over 2 comma text  the value of  end text P subscript 2 minus P subscript 1 equals

  1. fraction numerator 5 rho omega squared L squared over denominator 9 end fraction
  2. fraction numerator 5 rho omega squared L squared over denominator 18 end fraction
  3. fraction numerator 5 rho omega squared L squared over denominator 36 end fraction
  4. fraction numerator 5 rho omega squared L squared over denominator 72 end fraction

The correct answer is: fraction numerator 5 rho omega squared L squared over denominator 72 end fraction


    table attributes columnalign left columnspacing 1em rowspacing 4 pt end attributes row cell text  At  end text x equals L over 3 comma P subscript 1 equals P subscript 0 plus fraction numerator rho omega squared L squared over denominator 18 end fraction end cell row cell text  At  end text x equals L over 2 comma P subscript 2 equals P subscript 0 plus fraction numerator rho omega squared L squared over denominator 8 end fraction end cell row cell text  Now  end text P subscript 2 minus P subscript 1 equals rho omega squared L squared open parentheses 1 over 8 minus 1 over 18 close parentheses equals fraction numerator 5 rho omega squared L squared over denominator 72 end fraction end cell end table

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