Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Physics-

General

Easy

Question

A body starts from rest, with uniform acceleration. If its velocity after $n$ seconds is $v comma$ then its displacement in the last two seconds is

$\frac{2 v (n + 1)}{n}$
$\frac{v (n + 1)}{n}$
$\frac{v (n - 1)}{n}$
$\frac{2 v (n - 1)}{n}$

The correct answer is: $fraction numerator 2 v left parenthesis n minus 1 right parenthesis over denominator n end fraction$

$because v equals 0 plus n a rightwards double arrow a equals v divided by n$
Now, distance travelled in $n blank s e c$ . $rightwards double arrow S subscript n end subscript equals fraction numerator 1 over denominator 2 end fraction a n to the power of 2 end exponent$ and
distance travelled in $open parentheses n minus 2 close parentheses s e c rightwards double arrow S subscript n minus to the power of 2 end exponent end subscript equals fraction numerator 1 over denominator 2 end fraction a open parentheses n minus 2 close parentheses to the power of 2 end exponent$
$therefore D i s t a n c e blank t r a v e l l e d blank i n blank l a s t blank 2 blank s e c o n d s comma$
$equals S subscript n end subscript minus S subscript n minus 2 blank end subscript$ = $fraction numerator 1 over denominator 2 end fraction a n to the power of 2 end exponent minus fraction numerator 1 over denominator 2 end fraction a open parentheses n minus 2 close parentheses to the power of 2 end exponent$
$fraction numerator a over denominator 2 end fraction open square brackets n to the power of 2 end exponent minus open parentheses n minus 2 close parentheses to the power of 2 end exponent close square brackets equals fraction numerator a over denominator 2 end fraction open square brackets n plus open parentheses n minus 2 close parentheses close square brackets open square brackets n minus open parentheses n minus 2 close parentheses close square brackets$
$equals a open parentheses 2 n minus 2 close parentheses equals fraction numerator v over denominator n end fraction open parentheses 2 n minus 2 close parentheses equals fraction numerator 2 v left parenthesis n minus 1 right parenthesis over denominator n end fraction$

Related Questions to study

Two balls are dropped from height $h$ and $2 h$ respectively from the earth surface. The ratio of time of these balls to reach the earth is

Two balls are dropped from height $h$ and $2 h$ respectively from the earth surface. The ratio of time of these balls to reach the earth is

Physics-General

If the figure below represents a parabola, identify the physical quantities representing $Y blank a n d blank X$ for constant acceleration

If the figure below represents a parabola, identify the physical quantities representing $Y blank a n d blank X$ for constant acceleration

Physics-General

The motion of a particle is described by the equation $x equals a plus b t to the power of 2 end exponent$ where $a equals 15 blank c m$ and $b equals 3 blank c m divided by s to the power of 2 end exponent$ .Its instantaneous velocity at time $3 blank s e c$ will be

The motion of a particle is described by the equation $x equals a plus b t to the power of 2 end exponent$ where $a equals 15 blank c m$ and $b equals 3 blank c m divided by s to the power of 2 end exponent$ .Its instantaneous velocity at time $3 blank s e c$ will be

Physics-General

parallel

A body of mass $m$ is thrown upwards at an angle $theta$ with the horizontal with velocity $v.$ While rising up the velocity of the mass after $t$ second will be

A body of mass $m$ is thrown upwards at an angle $theta$ with the horizontal with velocity $v.$ While rising up the velocity of the mass after $t$ second will be

Physics-General

Starting from rest, acceleration of a particle is $a equals 2 open parentheses t minus 1 close parentheses$ . The velocity of the particle at $t equals 5 s$ is

Starting from rest, acceleration of a particle is $a equals 2 open parentheses t minus 1 close parentheses$ . The velocity of the particle at $t equals 5 s$ is

Physics-General

A ball is dropped from a high rise platform at $t equals 0$ starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed $v$ . The two balls meet at $t equals 18 s$ . What is the value of $v$ ? (taking $g equals 10 blank m divided by s to the power of 2 end exponent$ )

A ball is dropped from a high rise platform at $t equals 0$ starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed $v$ . The two balls meet at $t equals 18 s$ . What is the value of $v$ ? (taking $g equals 10 blank m divided by s to the power of 2 end exponent$ )

Physics-General

parallel

A balloon gong upward with a velocity of $12 blank m s to the power of negative 1 end exponent$ is at a height of 65 m from the earth’s surface at any instant. Exactly at this instant a ball drops from it. How much time will the ball take in reaching the surface of earth?
$open parentheses g equals 10 blank m s to the power of negative 2 end exponent close parentheses$

A balloon gong upward with a velocity of $12 blank m s to the power of negative 1 end exponent$ is at a height of 65 m from the earth’s surface at any instant. Exactly at this instant a ball drops from it. How much time will the ball take in reaching the surface of earth?
$open parentheses g equals 10 blank m s to the power of negative 2 end exponent close parentheses$

Physics-General

The graph of displacement-time for a body travelling in a straight line is given. We can conclude that

The graph of displacement-time for a body travelling in a straight line is given. We can conclude that

Physics-General

A balloon is rising vertically up with a velocity of $29 blank m s to the power of negative 1 end exponent.$ A stone is dropped from it and it reaches the ground in 10 s. The height of the balloon when the stone was dropped from it is $open parentheses g equals 9.8 blank m s to the power of negative 2 end exponent close parentheses$

A balloon is rising vertically up with a velocity of $29 blank m s to the power of negative 1 end exponent.$ A stone is dropped from it and it reaches the ground in 10 s. The height of the balloon when the stone was dropped from it is $open parentheses g equals 9.8 blank m s to the power of negative 2 end exponent close parentheses$

Physics-General

parallel

A particle moves along a straight line such that its displacement at any time $t$ is given by $S equals t to the power of 3 end exponent minus 6 t to the power of 2 end exponent plus 3 t plus 4 blank m e t r e s$
The velocity when the acceleration is zero is

A particle moves along a straight line such that its displacement at any time $t$ is given by $S equals t to the power of 3 end exponent minus 6 t to the power of 2 end exponent plus 3 t plus 4 blank m e t r e s$
The velocity when the acceleration is zero is

Physics-General

A body is released from a great height falls freely towards the earth. Another body is released from the same height exactly a second later. Then the separation between two bodies, 2 s after the release of the second body is, nearly

A body is released from a great height falls freely towards the earth. Another body is released from the same height exactly a second later. Then the separation between two bodies, 2 s after the release of the second body is, nearly

Physics-General

A body is moving along a straight line path with constant velocity.At an instant of time the distance travelled by it is S and its displacement is D, then

A body is moving along a straight line path with constant velocity.At an instant of time the distance travelled by it is S and its displacement is D, then

Physics-General

parallel

With what velocity a ball be projected vertically so that the distance covered by it in 5^th second is twice the distance it covers in its 6^th second ( $g equals 10 blank m divided by s to the power of 2 end exponent$ )

With what velocity a ball be projected vertically so that the distance covered by it in 5^th second is twice the distance it covers in its 6^th second ( $g equals 10 blank m divided by s to the power of 2 end exponent$ )

Physics-General

A bullet fired into a fixed target loses half of its velocity after penetrating $3 blank c m$ . How much further it will penetrate before coming to rest assuming that if faces constant resistance to motion

A bullet fired into a fixed target loses half of its velocity after penetrating $3 blank c m$ . How much further it will penetrate before coming to rest assuming that if faces constant resistance to motion

Physics-General

The displacement-time graphs of two particles $A$ and $B$ are straight lines making angles of respectively $30 degree$ and $60 degree$ with the time axis. If the velocity of $A$ is $v subscript A end subscript$ and that of $B$ is $v subscript B end subscript$ , then the value of $fraction numerator v subscript A end subscript over denominator v subscript B end subscript end fraction$ is

The displacement-time graphs of two particles $A$ and $B$ are straight lines making angles of respectively $30 degree$ and $60 degree$ with the time axis. If the velocity of $A$ is $v subscript A end subscript$ and that of $B$ is $v subscript B end subscript$ , then the value of $fraction numerator v subscript A end subscript over denominator v subscript B end subscript end fraction$ is

Physics-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.