Physics-
General
Easy

Question

A condenser having a capacity of 6 mu F is charged to 100 V and is then joined to an uncharged condenser of 14 mu F and then removed. The ratio of the charges on 6 mu F and 14 mu F and the potential of 6 mu F will be

  1. fraction numerator 6 over denominator 14 end fraction and 50   v o l t    
  2. fraction numerator 14 over denominator 6 end fraction and 30   v o l t    
  3. fraction numerator 6 over denominator 14 end fraction and 30   v o l t    
  4. fraction numerator 14 over denominator 6 end fraction and 0v o l t    

The correct answer is: fraction numerator 6 over denominator 14 end fraction and 30   v o l t


    Let q subscript 1 end subscript comma q subscript 2 end subscript be the charges on two condensers
    \ V equals fraction numerator q subscript 1 end subscript over denominator 6 end fraction equals fraction numerator q subscript 2 end subscript over denominator 14 end fraction Þ fraction numerator q subscript 1 end subscript over denominator q subscript 2 end subscript end fraction equals fraction numerator 6 over denominator 14 end fraction equals fraction numerator 3 over denominator 7 end fraction
    Also q subscript 1 end subscript plus q subscript 2 end subscript equals 600Þ q subscript 1 end subscript plus fraction numerator 14 over denominator 6 end fraction q subscript 1 end subscript equals 600Þ q subscript 1 end subscript equals fraction numerator 600 over denominator 20 end fraction cross times 6
    \ V equals fraction numerator q subscript 1 end subscript over denominator 6 end fraction equals fraction numerator 600 over denominator 20 end fraction equals 30 v o l t

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