Physics-
General
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Question

A flywheel has moment of inertia 4 kg-m2 and has kinetic energy of 200 J. Calculate the number of revolutions is makes before coming to rest if a constant opposing couple of 5N-m is applied to the flywheel -

  1. 12.8 rev  
  2. 24 rev  
  3. 6.4 rev  
  4. 16 rev  

The correct answer is: 6.4 rev


    W = KE or () = fraction numerator 1 over denominator 2 end fractionI2
    (2n) = fraction numerator 1 over denominator 2 end fractionI2

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