Physics-
General
Easy

Question

A Ge specimen is doped with Al. The concentration of acceptor atoms is tilde1021 atoms/m3. Given that the intrinsic concentration of electron hole pairs is tilde 1 0 to the power of 19 end exponent divided by m to the power of 3 end exponent, the concentration of electrons in the specimen is

  1. 1 0 to the power of 17 end exponent divided by m to the power of 3 end exponent    
  2. 1 0 to the power of 15 end exponent divided by m to the power of 3 end exponent    
  3. 1 0 to the power of 4 end exponent divided by m to the power of 3 end exponent    
  4. 1 0 to the power of 2 end exponent divided by m to the power of 3 end exponent    

The correct answer is: 1 0 to the power of 17 end exponent divided by m to the power of 3 end exponent


    n subscript i end subscript superscript 2 end superscript =n subscript h end subscript n subscript e end subscript rightwards double arrow left parenthesis 1 0 to the power of 19 end exponent right parenthesis to the power of 2 end exponent equals 1 0 to the power of 21 end exponent cross times n subscript e end subscript rightwards double arrow n subscript e end subscript equals 1 0 to the power of 17 end exponent divided by m to the power of 3 end exponent.

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