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Physics-

General

Easy

Question

What is the coordination number of sodium ions in the case of sodium chloride structure

6
8
4
12

The correct answer is: 6

In NaCl crystal Na⁺ ion is surrounded by 6 $C l to the power of minus end exponent$ ion, therefore coordination number of Na⁺ is 6.

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The expected energy of the electrons at absolute zero is called

The expected energy of the electrons at absolute zero is called

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If the series limit of Lymen series for Hydrogen atom is equal to the series limit of Balmer series for a hydrogen like atom, then atomic number o this hydrogen like atom will be

If the series limit of Lymen series for Hydrogen atom is equal to the series limit of Balmer series for a hydrogen like atom, then atomic number o this hydrogen like atom will be

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Consider an initially pure M gm sample of ^AX, an isotope that has a half life of T hour, what is it’s initial decay rate (N_A= Avogrado No.)

Consider an initially pure M gm sample of ^AX, an isotope that has a half life of T hour, what is it’s initial decay rate (N_A= Avogrado No.)

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Nuclear fission can be explained based on

Nuclear fission can be explained based on

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$text If end text c o s invisible function application 25 to the power of ring operator end exponent plus s i n invisible function application 25 to the power of ring operator end exponent equals$ K_t then cos $20 to the power of ring operator end exponent$ equal to

$text If end text c o s invisible function application 25 to the power of ring operator end exponent plus s i n invisible function application 25 to the power of ring operator end exponent equals$ K_t then cos $20 to the power of ring operator end exponent$ equal to

$text If end text c o s to the power of 2 end exponent invisible function application x plus c o s to the power of 4 end exponent invisible function application x equals 1 text , then the value of end text t a n to the power of 4 end exponent invisible function application x plus c o t to the power of 4 end exponent invisible function application x plus t a n to the power of 2 end exponent invisible function application x minus c o t to the power of 2 end exponent invisible function application x text is equal to end text$

$text If end text c o s to the power of 2 end exponent invisible function application x plus c o s to the power of 4 end exponent invisible function application x equals 1 text , then the value of end text t a n to the power of 4 end exponent invisible function application x plus c o t to the power of 4 end exponent invisible function application x plus t a n to the power of 2 end exponent invisible function application x minus c o t to the power of 2 end exponent invisible function application x text is equal to end text$

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If cot $theta equals fraction numerator square root of m plus square root of n over denominator square root of m minus square root of n end root end fraction$ ,then $left parenthesis m plus n right parenthesis$ cos $2 theta$ is equal to

If cot $theta equals fraction numerator square root of m plus square root of n over denominator square root of m minus square root of n end root end fraction$ ,then $left parenthesis m plus n right parenthesis$ cos $2 theta$ is equal to

On bombarding $U to the power of 235 end exponent$ by slow neutrons, 200MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be

On bombarding $U to the power of 235 end exponent$ by slow neutrons, 200MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be

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if cos $left parenthesis x minus y right parenthesis$ , cos x and cos $left parenthesis x plus y right parenthesis$ are in HP, then cos $x times s e c invisible function application fraction numerator y over denominator 2 end fraction$ is equal to

if cos $left parenthesis x minus y right parenthesis$ , cos x and cos $left parenthesis x plus y right parenthesis$ are in HP, then cos $x times s e c invisible function application fraction numerator y over denominator 2 end fraction$ is equal to

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if cot $alpha c o t invisible function application beta equals 2$ , then $fraction numerator c o s invisible function application left parenthesis alpha plus beta right parenthesis over denominator c o s invisible function application left parenthesis alpha minus beta right parenthesis end fraction$ is equal to

if cot $alpha c o t invisible function application beta equals 2$ , then $fraction numerator c o s invisible function application left parenthesis alpha plus beta right parenthesis over denominator c o s invisible function application left parenthesis alpha minus beta right parenthesis end fraction$ is equal to

Given $blank fraction numerator pi over denominator 2 end fraction less than alpha less than pi$ ,then the expression $square root of fraction numerator 1 minus s i n invisible function application alpha over denominator 1 plus s i n invisible function application alpha end fraction end root plus square root of fraction numerator 1 plus s i n invisible function application alpha over denominator 1 minus s i n invisible function application alpha end fraction end root$ s equal to $blank$

Given $blank fraction numerator pi over denominator 2 end fraction less than alpha less than pi$ ,then the expression $square root of fraction numerator 1 minus s i n invisible function application alpha over denominator 1 plus s i n invisible function application alpha end fraction end root plus square root of fraction numerator 1 plus s i n invisible function application alpha over denominator 1 minus s i n invisible function application alpha end fraction end root$ s equal to $blank$

$text Find the value of end text x text if end text x equals fraction numerator 1 minus 4 s i n invisible function application 10 to the power of ring operator end exponent s i n invisible function application 70 to the power of ring operator end exponent over denominator 2 s i n invisible function application 10 to the power of ring operator end exponent end fraction text . end text$

$text Find the value of end text x text if end text x equals fraction numerator 1 minus 4 s i n invisible function application 10 to the power of ring operator end exponent s i n invisible function application 70 to the power of ring operator end exponent over denominator 2 s i n invisible function application 10 to the power of ring operator end exponent end fraction text . end text$

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If |sinx + cosx| = |sinx| + |cosx|, then x belongs to the quadrant

If |sinx + cosx| = |sinx| + |cosx|, then x belongs to the quadrant

$text If end text x comma y comma z text are in AP, then end text fraction numerator s i n invisible function application x minus s i n invisible function application z over denominator c o s invisible function application z minus c o s invisible function application x end fraction text is equal to end text$

$text If end text x comma y comma z text are in AP, then end text fraction numerator s i n invisible function application x minus s i n invisible function application z over denominator c o s invisible function application z minus c o s invisible function application x end fraction text is equal to end text$

$s i n invisible function application fraction numerator pi over denominator 9 end fraction s i n invisible function application fraction numerator 2 pi over denominator 9 end fraction s i n invisible function application fraction numerator 4 pi over denominator 9 end fraction s i n invisible function application fraction numerator pi over denominator 3 end fraction text is equal to end text$

$s i n invisible function application fraction numerator pi over denominator 9 end fraction s i n invisible function application fraction numerator 2 pi over denominator 9 end fraction s i n invisible function application fraction numerator 4 pi over denominator 9 end fraction s i n invisible function application fraction numerator pi over denominator 3 end fraction text is equal to end text$

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